[Question] Regulating resources

[sjehuda]

Good day, to one and all!

I am involved with a Python project called Blasta - An XMPP PubSub based annotation system.

blasta720p.mp4

Screenshots https://git.xmpp-it.net/sch/Blasta/src/branch/main/screenshot

The system is an annotation (also referred to as bibliography and bookmarks) management system.

I do not desire to open resources from within TkinterWeb.

Which means that using the module webbrowser is more viable over pywebview, unless it is possible to regulate access.

import webbrowser
webbrowser.open('http://localhost:8000')

python blasta.py
python -m webbrowser -t 'http://localhost:8000'

Is it possible to block or treat differently to resources outside of specified hostnames?

This matter was raise at r0x0r/pywebview#1459

[Andereoo]

Hi! I assume you looking to intercept all requests (images, stylesheets, etc) and not block the loading of all external resources all together?

[sjehuda]

Not exactly. I want to ignore or treat differently, any resource that is not of the original hostname. I have made an HTML service (Blasta). I want to utilize it as a desktop software, and so I do not want to allow opening of any link within the software itself; instead, I want any foreign resource (i.e. URL or URI) to open outside of the software. See the argument r0x0r/pywebview#1459 And the use case r0x0r/pywebview#1461 (comment) I suppose, that I will contribute code to pywebview (they really should rename the project to pyhtmlview), in order to do so. The author has made some initial work on that matter. Nevertheless, I am also interested to utilize TkinterWeb as a toolkit for desktop software, because it is even more lightweight.

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On Fri, 11 Oct 2024 07:08:29 -0700 Andrew ***@***.***> wrote: Hi! I assume you looking to intercept all requests (images, stylesheets, etc) and not block the loading of all external resources all together?

[Andereoo]

Yes, that is quite easy to do. From the API Reference, can use on_link_click to override the default behaviour for hyperlinks and on_form_submit to handle form submissions. For instance, the following would open the resource in the default webbrowser rather than displaying it in TkinterWeb:

def load_new_page(url):
    webbrowser.open(url)
    
myhtmlframe.on_link_click(load_new_page)