How to invoke the new http_status_reply for unusual statuses
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Throwing divide by zero or soemthing will generate 500, and no handler will generate 404, but what about something like 403 forbidden?
My impression is that there's some exception I can throw?
Assigning to Jan to get clarity. Then annie will fix.
There are two replies: throw(http_reply(Term)), where Term is handed to
http://www.swi-prolog.org/pldoc/man?predicate=http_status_reply/4, which isn't very well documented :( The source should be pretty clear though :)
The other is to formulate a normal reply (the way you do for 200) and add a header the usual
way:
format('Status: 403 forbidden~n')
Thus, for a normal CGI-style response the system will add 200 OK if there is no status header
and the provided one otherwise.
@Anniepoo Where did you find a predicate named http_status_page?
closed fixed