又双叒更新了

Question

又双叒更新了

Opened this issue 5 years ago · 25 comments

callback: jQuery110208448685595287795_1588213215377
fpdm: 011001600211
fphm: 12412412
r: 0.5140375363656053
v: V2.0.03_001
nowtime: 1588215652582
publickey: 0E4A6CDDAFCC4687986D13F2027E2B50
key9: e2243655225930a88366a5c0c20e753c
_: 1588213215390
flwq39: WfuTVayxbBZFRcuVwLn1tEkN98Rl2GFfR5n6qeJ9K17djSc14EN7o8grOnF21Vikhrcvxyp8Lz89znRqkOL79rAixP9qllQGVC639L18ZVymI3La97FrcvY3PRcNEAFpExoFhu6+06yBP8Q4epeoDByXvY02vgcpVwgyRNBjELA=

Answer 1 · 2020-04-30T03:17:53.000Z

key9:
yuqet.js 里的
$[_0x3c85('0x29')]['cy'] = function(_0x4caced, _0x22f8eb, _0xa37456)

$[_0x3c85('0x29')][_0x3c85('0x2a')] = function(_0x5db4e8, _0x53ad84, _0x11f8e9)

Answer 2 · 2020-04-30T03:22:04.000Z

我吐了，我严重怀疑他们在看我们，我们刚搞出来他们就加一个签名

Answer 3 · 2020-04-30T03:36:40.000Z

哈，我刚准备问key9哪来的

Answer 4 · 2020-04-30T03:44:27.000Z

这页面里的js复杂度是我人生中见过最复杂的

Answer 5 · 2020-04-30T08:59:03.000Z

加油，持续搞定他

Answer 6 · 2020-04-30T10:53:41.000Z

public static String key9(String key1, String key2, String yzmSj){
    String k = key1 + key2;
    String kk = key1+key2+key2+key1;
    String kkk = key1+key1+key2+key1+key2+key2 ;
    String one = "123456" + chuyu(k, Integer.valueOf(key2)%2);
    String six = "654321" + chuyu(kk,Integer.valueOf(key2)%2);
    String ko =  toK(kkk);
    String[] chars = ko.split("");

    TreeSet<String> treeSet = new TreeSet();
    for (String s : chars) {
        treeSet.add(s);
    }
    //把treeSet拼接成字符串
    ko = "";
    for (String s : treeSet) {
        ko += s;
    }



    k = toK(k.substring(0,8)) + toK(k.substring(8));
    kk = toK(kk.substring(0,9)) +toK(kk.substring(9,17)) +toK(kk.substring(17));
    kkk = toK(kkk.substring(0,15)) +toK(kkk.substring(15,30)) +toK(kkk.substring(30));

    System.out.println(k);
    System.out.println(kk);
    System.out.println(kkk);

    System.out.println(ko);
    System.out.println(one);
    System.out.println(six);
    String k3 = encrypt(    encrypt(ko)+ ko.length()*7 +
            gen( toSub(ko) ,  encode(toSub(ko) ))
            ).toUpperCase();

    System.out.println(encrypt(encrypt(yzmSj) + yzmSj.length() * 7 +
            gen(toSub(yzmSj), encode(toSub(yzmSj)))
    ).toUpperCase());
    System.out.println(k3);
    String k4 = encrypt(key1) + encrypt(key2) + encrypt(yzmSj) + encrypt(k) +encrypt(kk) +encrypt(kkk)
            + encrypt(one) +encrypt(six) +encrypt(k3) + kkkkk(k,kk,kkk,one);
    System.out.println(k4);
    String k5 =  k4 +  kkkkk(one,six,key1,yzmSj) +
            encrypt(    encrypt(yzmSj)+ yzmSj.length()*7 +
                    gen( toSub(yzmSj) ,  encode(toSub(yzmSj) ))
            ).toUpperCase();
    System.out.println(k5);
    String k6 = encrypt(  k5 +encrypt(key1) + encrypt(key2) + encrypt(yzmSj)  )   ;

    System.out.println(k6);
    return k6;

}
public static String toK(String k ){
    char [] arr = k.toCharArray();
    Arrays.sort(arr);
    String sortedStr=new String(arr);  //加上这句
    return sortedStr;
}

public static String chuyu(String k , int i ){
    String str = "";
    char [] arr = k.toCharArray();
    for (char s : arr) {
       if( s % 2  == i ){
           str += s;
       }

    }
    return str;
}


public static String kkkkk(String k1,String k2,String k3,String k4){
    return  encrypt(     encrypt(k1)+ k2.length()*7  +  gen( toSub(k3)  ,encode( toSub(k4)) )  ).toUpperCase();
}
public static String gen(String n, String c) {
    String d = encrypt(n);
    String i = encrypt(n) + c;
    String h = "402880bd5c76101f015c903ee811504e";
    return encrypt(d + i + h + n.trim().length()).toUpperCase();
}

Answer 7 · 2020-04-30T10:55:36.000Z

我天，你也太快了，你是魔鬼吧😃

Answer 8 · 2020-04-30T12:53:07.000Z

public static String key9(String key1, String key2, String yzmSj){
    String k = key1 + key2;
    String kk = key1+key2+key2+key1;
    String kkk = key1+key1+key2+key1+key2+key2 ;
    String one = "123456" + chuyu(k, Integer.valueOf(key2)%2);
    String six = "654321" + chuyu(kk,Integer.valueOf(key2)%2);
    String ko =  toK(kkk);
    String[] chars = ko.split("");

    TreeSet<String> treeSet = new TreeSet();
    for (String s : chars) {
        treeSet.add(s);
    }
    //把treeSet拼接成字符串
    ko = "";
    for (String s : treeSet) {
        ko += s;
    }



    k = toK(k.substring(0,8)) + toK(k.substring(8));
    kk = toK(kk.substring(0,9)) +toK(kk.substring(9,17)) +toK(kk.substring(17));
    kkk = toK(kkk.substring(0,15)) +toK(kkk.substring(15,30)) +toK(kkk.substring(30));

    System.out.println(k);
    System.out.println(kk);
    System.out.println(kkk);

    System.out.println(ko);
    System.out.println(one);
    System.out.println(six);
    String k3 = encrypt(    encrypt(ko)+ ko.length()*7 +
            gen( toSub(ko) ,  encode(toSub(ko) ))
            ).toUpperCase();

    System.out.println(encrypt(encrypt(yzmSj) + yzmSj.length() * 7 +
            gen(toSub(yzmSj), encode(toSub(yzmSj)))
    ).toUpperCase());
    System.out.println(k3);
    String k4 = encrypt(key1) + encrypt(key2) + encrypt(yzmSj) + encrypt(k) +encrypt(kk) +encrypt(kkk)
            + encrypt(one) +encrypt(six) +encrypt(k3) + kkkkk(k,kk,kkk,one);
    System.out.println(k4);
    String k5 =  k4 +  kkkkk(one,six,key1,yzmSj) +
            encrypt(    encrypt(yzmSj)+ yzmSj.length()*7 +
                    gen( toSub(yzmSj) ,  encode(toSub(yzmSj) ))
            ).toUpperCase();
    System.out.println(k5);
    String k6 = encrypt(  k5 +encrypt(key1) + encrypt(key2) + encrypt(yzmSj)  )   ;

    System.out.println(k6);
    return k6;

}
public static String toK(String k ){
    char [] arr = k.toCharArray();
    Arrays.sort(arr);
    String sortedStr=new String(arr);  //加上这句
    return sortedStr;
}

public static String chuyu(String k , int i ){
    String str = "";
    char [] arr = k.toCharArray();
    for (char s : arr) {
       if( s % 2  == i ){
           str += s;
       }

    }
    return str;
}


public static String kkkkk(String k1,String k2,String k3,String k4){
    return  encrypt(     encrypt(k1)+ k2.length()*7  +  gen( toSub(k3)  ,encode( toSub(k4)) )  ).toUpperCase();
}
public static String gen(String n, String c) {
    String d = encrypt(n);
    String i = encrypt(n) + c;
    String h = "402880bd5c76101f015c903ee811504e";
    return encrypt(d + i + h + n.trim().length()).toUpperCase();
}

sixsixsixsix

Answer 9 · 2020-05-06T04:52:32.000Z

为啥我试了还是 “系统异常，请重试！”，求教大神

Answer 10 · 2020-05-06T07:26:45.000Z

首先图片获取，大部分参数是不检验的，只有有参数，就能直接获取到不知道你时哪里错误
发现 encrypt 其实是MD5 encode 是 base64
我读取信息的 publicKey 如下
public static String publicKey(String fpdm, String fphm, String yzmSj) {
String[] a = new String[]{"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"};
String[] b = new String[]{"0", "9", "2", "8", "4", "5", "6", "7", "3", "1"};
int c = Integer.valueOf(fpdm.substring(2, 3));
String d = a[Integer.valueOf(b[c])];
String e = encrypt(d + a[2] + "i" + encrypt(yzmSj));

    String f = encrypt(fphm + moveTo(fpdm.substring(0, 11)) + moveTo(e)) +
            encode(fphm + moveTo(encrypt(fphm + e.length())).toUpperCase()) +
            gen(fphm.substring(0, 2), (fpdm + e).length() * 7 + "").toUpperCase();
    f = encrypt(f);
    return f;
}

Answer 11 · 2020-05-06T07:41:52.000Z

public static String key9(String key1, String key2, String yzmSj){
    String k = key1 + key2;
    String kk = key1+key2+key2+key1;
    String kkk = key1+key1+key2+key1+key2+key2 ;
    String one = "123456" + chuyu(k, Integer.valueOf(key2)%2);
    String six = "654321" + chuyu(kk,Integer.valueOf(key2)%2);
    String ko =  toK(kkk);
    String[] chars = ko.split("");

    TreeSet<String> treeSet = new TreeSet();
    for (String s : chars) {
        treeSet.add(s);
    }
    //把treeSet拼接成字符串
    ko = "";
    for (String s : treeSet) {
        ko += s;
    }



    k = toK(k.substring(0,8)) + toK(k.substring(8));
    kk = toK(kk.substring(0,9)) +toK(kk.substring(9,17)) +toK(kk.substring(17));
    kkk = toK(kkk.substring(0,15)) +toK(kkk.substring(15,30)) +toK(kkk.substring(30));

    System.out.println(k);
    System.out.println(kk);
    System.out.println(kkk);

    System.out.println(ko);
    System.out.println(one);
    System.out.println(six);
    String k3 = encrypt(    encrypt(ko)+ ko.length()*7 +
            gen( toSub(ko) ,  encode(toSub(ko) ))
            ).toUpperCase();

    System.out.println(encrypt(encrypt(yzmSj) + yzmSj.length() * 7 +
            gen(toSub(yzmSj), encode(toSub(yzmSj)))
    ).toUpperCase());
    System.out.println(k3);
    String k4 = encrypt(key1) + encrypt(key2) + encrypt(yzmSj) + encrypt(k) +encrypt(kk) +encrypt(kkk)
            + encrypt(one) +encrypt(six) +encrypt(k3) + kkkkk(k,kk,kkk,one);
    System.out.println(k4);
    String k5 =  k4 +  kkkkk(one,six,key1,yzmSj) +
            encrypt(    encrypt(yzmSj)+ yzmSj.length()*7 +
                    gen( toSub(yzmSj) ,  encode(toSub(yzmSj) ))
            ).toUpperCase();
    System.out.println(k5);
    String k6 = encrypt(  k5 +encrypt(key1) + encrypt(key2) + encrypt(yzmSj)  )   ;

    System.out.println(k6);
    return k6;

}
public static String toK(String k ){
    char [] arr = k.toCharArray();
    Arrays.sort(arr);
    String sortedStr=new String(arr);  //加上这句
    return sortedStr;
}

public static String chuyu(String k , int i ){
    String str = "";
    char [] arr = k.toCharArray();
    for (char s : arr) {
       if( s % 2  == i ){
           str += s;
       }

    }
    return str;
}


public static String kkkkk(String k1,String k2,String k3,String k4){
    return  encrypt(     encrypt(k1)+ k2.length()*7  +  gen( toSub(k3)  ,encode( toSub(k4)) )  ).toUpperCase();
}
public static String gen(String n, String c) {
    String d = encrypt(n);
    String i = encrypt(n) + c;
    String h = "402880bd5c76101f015c903ee811504e";
    return encrypt(d + i + h + n.trim().length()).toUpperCase();
}

这部分有js吗？

Answer 12 · 2020-05-06T08:07:47.000Z

前面获取图片、数据解码都OK的，就最后提交vatQuery接口请求，一直报“系统异常，请重试！”，很难找到是哪个参数不行

Answer 13 · 2020-05-06T08:11:47.000Z

@carrytameng 你用Chrome抓一下包，对比分析一下参数呗，flwq39每次都不一样，但是别的应该差不多。

Answer 14 · 2020-05-07T00:25:34.000Z

前面获取图片、数据解码都OK的，就最后提交vatQuery接口请求，一直报“系统异常，请重试！”，很难找到是哪个参数不行

我用selenium来自动测试也是报这个错，我用的Chrome 81.0 ，而后我换成它官方推荐的Chrome 55之后就可以查询了，同一张发票。你可以试试 request post的时候改一下 user-agent试试看吧，我没测试。

Answer 15 · 2020-05-07T00:36:57.000Z

Webdriver行不通，因为它4月更新有反自动化的东西，会识别webdriver

Answer 16 · 2020-05-07T00:39:57.000Z

Webdriver行不通，因为它4月更新有反自动化的东西，会识别webdriver

好吧，难怪好好的突然怎么就用不了了，原来反爬了。

Answer 17 · 2020-05-07T09:47:12.000Z

Webdriver行不通，因为它4月更新有反自动化的东西，会识别webdriver

把window.navigator.webdriver值改成undefined之后可以破解它的反自动化爬取，页面上有能正确查询发票，但是我用mimtdump脚本抓取到response.text的时候，返回的数据确是一堆字母，形如下：{"data": "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"}，所以这个就是你们说的那个flwq39加密吗？

Answer 18 · 2020-05-07T09:51:26.000Z

flwq39那个是请求时候的签名，服务端校验之后决定是否正常返回，你这个data是正常返回之后的加密数据，需要解密，之前验证码返回的data加密我已经破解过了，这个不确定和验证码那里的是不是一样，估计这破网站的尿性，应该是不一样的算法。

Answer 19 · 2020-05-14T01:42:49.000Z

我用你的yzm.py,返回是这个InsecureRequestWarning: Unverified HTTPS request is being made. Adding certificate verification is strongly advised. See: https://urllib3.readthedocs.io/en/latest/advanced-usage.html#ssl-warnings
InsecureRequestWarning)
({'key1': 'errv', 'key2': '', 'key3': '', 'key4': ''}, <requests.sessions.Session object at 0x00000238E3C658D0>)，这个需要如何处理？请指教，谢谢

Answer 20 · 2020-05-14T02:30:59.000Z

你的程序发的内容是：GET https://fpcy.anhui.chinatax.gov.cn/NWebQuery/yzmQuery?callback=jQuery1102045870758052653293_1581247300793&fpdm=034151900111&fphm=00867099&r=0.2992333402900412&v=V2.0.02_002&nowtime=1589423189354&area=3400&publickey=EA6378C03A420E78059707B76ECEF8FC HTTP/1.1
Host: fpcy.anhui.chinatax.gov.cn
user-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/76.0.3809.100 Safari/537.36
Accept-Encoding: gzip, deflate
Accept: /
Connection: keep-alive
正确的包内容是
GET https://fpcy.anhui.chinatax.gov.cn/NWebQuery/yzmQuery?callback=jQuery11020530547570930477_1589423009798&fpdm=034151900111&fphm=00867099&r=0.7243047684178852&v=V2.0.03_002&nowtime=1589423135474&publickey=EF362E19350D49B44E7B65F34CB6505D&key9=a6950f0477a490c89fdcbcf7eaa7ef6a&_=1589423009800&flwq39=Dg%2BnbyFZbAeGHZR4JN%2FoTCoMVZiDDH9bM6NlMzyNbOOE9wk36%2Fm5nJ6b2CDzoag4A8WFnCxLI78XSTczrqvXCE9YHGqXhUCNfRz9s%2BNwQXwv5LAAnV9aoUaM4LkuRqInTu86qMFS61sihSFdABUFdzv2FoxNT7yj8KWhL6HRYIU%3D HTTP/1.1
Host: fpcy.anhui.chinatax.gov.cn
Connection: keep-alive
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36
Accept: /
Referer: https://inv-veri.chinatax.gov.cn/index.html
Accept-Encoding: gzip, deflate, br
Accept-Language: zh-CN,zh;q=0.9
Cookie: yfx_c_g_u_id_10000056=_ck20042108535617612651191767091; yfx_f_l_v_t_10000056=f_t_1587430436734__r_t_1587430436734__v_t_1587430436734__r_c_0; yfx_mr_10000056=%3A%3Amarket_type_free_search%3A%3A%3A%3Abaidu%3A%3A%3A%3A%3A%3A%3A%3Awww.baidu.com%3A%3A%3A%3Apmf_from_free_search; yfx_mr_f_10000056=%3A%3Amarket_type_free_search%3A%3A%3A%3Abaidu%3A%3A%3A%3A%3A%3A%3A%3Awww.baidu.com%3A%3A%3A%3Apmf_from_free_search; yfx_key_10000056=; JSESSIONID=ZOcQ6QA7D6jri_Bdtg7wpASMM_aY3_X9THJuIebQJWbjVKrkLU-m!-498538042; fpcyhhbc=49228713

是不是必须要有cookie才可以？请指教

Answer 21 · 2020-05-14T02:38:45.000Z

和cookie没有关系，前端时间更新了两个签名flwq39和key9其中flwq39我已经破解完成了，但是目前只有js版本的，没有加到python里，key9还没有时间破解。

Answer 22 · 2020-05-14T02:47:04.000Z

明白了，谢谢，只能用selenium来查发票,就是速度很慢

Answer 23 · 2020-05-18T09:22:35.000Z

public static String key9(String key1, String key2, String yzmSj){
    String k = key1 + key2;
    String kk = key1+key2+key2+key1;
    String kkk = key1+key1+key2+key1+key2+key2 ;
    String one = "123456" + chuyu(k, Integer.valueOf(key2)%2);
    String six = "654321" + chuyu(kk,Integer.valueOf(key2)%2);
    String ko =  toK(kkk);
    String[] chars = ko.split("");

    TreeSet<String> treeSet = new TreeSet();
    for (String s : chars) {
        treeSet.add(s);
    }
    //把treeSet拼接成字符串
    ko = "";
    for (String s : treeSet) {
        ko += s;
    }



    k = toK(k.substring(0,8)) + toK(k.substring(8));
    kk = toK(kk.substring(0,9)) +toK(kk.substring(9,17)) +toK(kk.substring(17));
    kkk = toK(kkk.substring(0,15)) +toK(kkk.substring(15,30)) +toK(kkk.substring(30));

    System.out.println(k);
    System.out.println(kk);
    System.out.println(kkk);

    System.out.println(ko);
    System.out.println(one);
    System.out.println(six);
    String k3 = encrypt(    encrypt(ko)+ ko.length()*7 +
            gen( toSub(ko) ,  encode(toSub(ko) ))
            ).toUpperCase();

    System.out.println(encrypt(encrypt(yzmSj) + yzmSj.length() * 7 +
            gen(toSub(yzmSj), encode(toSub(yzmSj)))
    ).toUpperCase());
    System.out.println(k3);
    String k4 = encrypt(key1) + encrypt(key2) + encrypt(yzmSj) + encrypt(k) +encrypt(kk) +encrypt(kkk)
            + encrypt(one) +encrypt(six) +encrypt(k3) + kkkkk(k,kk,kkk,one);
    System.out.println(k4);
    String k5 =  k4 +  kkkkk(one,six,key1,yzmSj) +
            encrypt(    encrypt(yzmSj)+ yzmSj.length()*7 +
                    gen( toSub(yzmSj) ,  encode(toSub(yzmSj) ))
            ).toUpperCase();
    System.out.println(k5);
    String k6 = encrypt(  k5 +encrypt(key1) + encrypt(key2) + encrypt(yzmSj)  )   ;

    System.out.println(k6);
    return k6;

}
public static String toK(String k ){
    char [] arr = k.toCharArray();
    Arrays.sort(arr);
    String sortedStr=new String(arr);  //加上这句
    return sortedStr;
}

public static String chuyu(String k , int i ){
    String str = "";
    char [] arr = k.toCharArray();
    for (char s : arr) {
       if( s % 2  == i ){
           str += s;
       }

    }
    return str;
}


public static String kkkkk(String k1,String k2,String k3,String k4){
    return  encrypt(     encrypt(k1)+ k2.length()*7  +  gen( toSub(k3)  ,encode( toSub(k4)) )  ).toUpperCase();
}
public static String gen(String n, String c) {
    String d = encrypt(n);
    String i = encrypt(n) + c;
    String h = "402880bd5c76101f015c903ee811504e";
    return encrypt(d + i + h + n.trim().length()).toUpperCase();
}

key9应该是 _0x3f04ae['prototype']['yzm'] = function(_0x30e042, _0x46d655, _0xd57abe) 这个函数吧？

Answer 24 · 2020-07-07T02:24:15.000Z

这个文章好像能完美解决key问题https://blog.csdn.net/qq_35228149/article/details/106818057

Answer 25 · 2020-11-26T10:34:26.000Z

我做成服务接口，见https://blog.csdn.net/Open_CV_NLP/article/details/109828259