67.实现一个sum函数
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const sum = (...args1) => {
let fullArgs = [...args1];
const fn = (...args2) => {
// 收集参数
fullArgs = [...fullArgs, ...args2];
// 返回自身保持链式调用
return fn;
};
// 重写valueOf, 累加已收集的集数
fn.valueOf = () => {
return fullArgs.reduce((total, cur) => (total+=cur), 0);
}
return fn
}
const sum = (...args1) => {
let fullArgs = [...args1];
const fn = (...args2) => {
fullArgs = [...fullArgs, ...args2]
return fn;
}
fn.valueOf = () =>
return fullArgs.reduce((total, cur) => total += cur, 0);
}
return fn;
}