Feature Request - add Mean Radiant Temperature

Question

Feature Request - add Mean Radiant Temperature

Closed this issue 7 years ago · 7 comments

Would you consider adding MRT as a message input value? This would be useful for me.

Answer 1 · 2018-01-03T08:48:37.000Z

I also see that I cannot include the airspeed in the message. That would also be useful for me.

Answer 2 · 2018-01-03T08:52:40.000Z

Are you sure? I just checked and it defaults to a static number but you can change it with the drop down to a msg or context property. I'm working on MRT at the moment. On Wednesday, 3 January 2018 18:48:38 AEST Colin Law wrote: I also see that I cannot include the airspeed in the message. That would also be useful for me. —You are receiving this because you are subscribed to this thread.Reply to this email directly, view it on GitHub[1], or mute the thread[2].[3]

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Answer 3 · 2018-01-03T08:56:46.000Z

Oh, no I didn't try it. I was just looking at the code which has
node.airspeedField = n.airspeedField || 0;
node.airspeedFieldType = n.airspeedFieldType || "num";
but I don't understand fully how this works so you may well be right. I will try it later.

Answer 4 · 2018-01-03T08:59:56.000Z

Those are just default values if the config is missing. You can set it to get any of the parameters to come from msg, flow, or global properties, or set them to a static value. On Wednesday, 3 January 2018 18:56:47 AEST Colin Law wrote: Oh, no I didn't try it. I was just looking at the code which hasnode.airspeedField = n.airspeedField || 0;node.airspeedFieldType = n.airspeedFieldType || "num";but I don't understand fully how this works so you may well be right. I will try it later. —You are receiving this because you commented.Reply to this email directly, view it on GitHub[1], or mute the thread[2].[3]

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Answer 5 · 2018-01-03T09:08:09.000Z

Ah, yes, you are right. Sorry.

Answer 6 · 2018-01-03T14:26:38.000Z

MRT input has been added. It can be set to a property or static value, or set to operative in which case it will be the same as the air temperature.

Answer 7 · 2018-01-03T16:00:58.000Z

Great, working well for me, many thanks.