Misleading example on December-01?
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Well, I might be wrong, but to my mind the 10th sevenish number should be 392, not 350.
Am I missing something or is the example in error?
My 10 first sevenish numbers: 1, 7, 8, 49, 50, 56, 343, 344, 350, 392
@atarv As I understand it, 350 is the correct 10th sevenish number.
The ten first sevenish numbers are as follows:
1 (7^0), 7 (7^1), 8, 49 (7^2), 50, 56, 57, 343 (7^3), 344, 350
You are missing 57, which is sum(1, 7, 49).
Admittedly, the wording of the problem and the given data are a little ambiguous.
Ah, I see. So a sevenish number is a sum of any (positive) number of unique powers of 7. Is that correct?
@atarv yes, your definition of the problem is right. The ten first sevenish numbers pointed out by @alirezaghey is the correct one.