Sunny-117/js-challenges

n个2的n次方之和

Sunny-117 opened this issue · 3 comments

n个2的n次方之和

等比数列求和吧

等比数列求和公式

  • Sn = a1 * (q**n - 1) / (q - 1)
function sumOfPowers(n) {
  let sum = 0;
  for (let i = 0; i < n; i++) {
    sum += Math.pow(2, i);
  }
  return sum;
}