二叉树的最近公共祖先
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hannah-bingo commented
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @param {TreeNode} p
* @param {TreeNode} q
* @return {TreeNode}
*/
var lowestCommonAncestor = function(root, p, q) {
if(root === null) return null
if(root === p || root === q) return root
let left = lowestCommonAncestor(root.left, p, q)
let right = lowestCommonAncestor(root.right, p, q)
if(left === null && right === null) return null;
if(left !== null && right !== null) return root;
return left === null ? right : left;
};