Incorret flags.DEFINE_boolean() behavior

[AshiakerWang]

demo python script

from absl import app
from absl import flags
FLAGS = flags.FLAGS
flags.DEFINE_boolean('tea',True,'Soggy Leaves')
def test(unused_argv):
   if FLAGS.tea:
        print( "have some tea" )
   else:
        print( "no tea" )
if __name__ == '__main__':
   app.run(test)

The following output is expected while executing python test2.py --tea False in the command line

• no tea

However, the actual output while executing python test2.py --tea False is

• have some tea

In other words, no matter which boolean argument(i.e. True or False) is set in the command line, the output of the demo python script remains unchanged.

[AshiakerWang]

Here is a screenshot of my code running results.

[gpshead]

boolean flags do not take an additional argument. --tea means True. --notea means False. --tea=True and --tea=False and related true/false values after = also work.

[AshiakerWang]

Thanks for your explanation!