[BUG] Video class doesn't work - 400 Bad Request

Question

[BUG] Video class doesn't work - 400 Bad Request

Closed this issue 3 years ago · 21 comments

If I try and use anything in from extras.py I just get this

  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 42, in __makeRequest
    response = urlopen(request)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 214, in urlopen
    return opener.open(url, data, timeout)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 523, in open
    response = meth(req, response)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 632, in http_response
    response = self.parent.error(
  File "D:\Program Files\Python39\lib\urllib\request.py", line 561, in error
    return self._call_chain(*args)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 494, in _call_chain
    result = func(*args)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 641, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "c:\Users\Alucard\Desktop\ytalbumdl-source\test.py", line 4, in <module>
    print(Video.getInfo('https://www.youtube.com/watch?v=SCHpzvmw_PU'))
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\extras.py", line 337, in getInfo        
    return Video(videoLink, "getInfo", mode).result
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 11, in __init__
    statusCode = self.__makeRequest(self.__getVideoId(videoLink))
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 46, in __makeRequest
    raise Exception('ERROR: Could not make request.')
Exception: ERROR: Could not make request.```

Answer 1 · 2021-09-14T01:37:47.000Z

I tried to use Video.getInfo for this example but the same happens with everything from extras

Answer 2 · 2021-09-14T01:50:35.000Z

Started getting this today too, it seems if you attempt it multiple times it will sometimes work and sometimes not. My guess is youtube attempting to prevent downloading.

Answer 3 · 2021-09-14T01:56:28.000Z

I'm guessing that too, since it does it with older versions as well

Answer 4 · 2021-09-14T02:48:12.000Z

so basically youtube-search-python is broken until further notice?

Answer 5 · 2021-09-14T02:49:22.000Z

so basically youtube-search-python is broken until further notice?

So far it only seems like this error happens when using Video.get() not VideoSearch() so that second one should work

Answer 6 · 2021-09-14T02:55:13.000Z

is there any alternate way of getting a title from a url or the id?

Answer 7 · 2021-09-14T02:57:04.000Z

Not that I've seen, my solution would be to just attempt the download over and over on error since it seems to work some of the time

Answer 8 · 2021-09-14T03:04:09.000Z

not working for me I ran it over 500 times and none of them succeeded, so that sucks

Answer 9 · 2021-09-14T05:01:51.000Z

If I try and use anything in from extras.py I just get this

  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 42, in __makeRequest
    response = urlopen(request)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 214, in urlopen
    return opener.open(url, data, timeout)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 523, in open
    response = meth(req, response)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 632, in http_response
    response = self.parent.error(
  File "D:\Program Files\Python39\lib\urllib\request.py", line 561, in error
    return self._call_chain(*args)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 494, in _call_chain
    result = func(*args)
  File "D:\Program Files\Python39\lib\urllib\request.py", line 641, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "c:\Users\Alucard\Desktop\ytalbumdl-source\test.py", line 4, in <module>
    print(Video.getInfo('https://www.youtube.com/watch?v=SCHpzvmw_PU'))
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\extras.py", line 337, in getInfo        
    return Video(videoLink, "getInfo", mode).result
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 11, in __init__
    statusCode = self.__makeRequest(self.__getVideoId(videoLink))
  File "D:\Program Files\Python39\lib\site-packages\youtubesearchpython\internal\extras.py", line 46, in __makeRequest
    raise Exception('ERROR: Could not make request.')
Exception: ERROR: Could not make request.```

Hello!
YouTube is currently changing a lot of things on its API. I have fixed StreamURLFetcher a while ago, and back then everything worked.
Let me have a look

Answer 10 · 2021-09-14T05:11:45.000Z

After further investigation, I have found that only one class is reproducing this error, and that is Video class - others aren't. I will see what I can do

Answer 11 · 2021-09-14T05:33:33.000Z

After further investigation, I have found that only one class is reproducing this error, and that is Video class - others aren't. I will see what I can do

I also had this exact same issue with the Playlist class

Answer 12 · 2021-09-14T05:35:11.000Z

YouTube is messing around again.

Answer 13 · 2021-09-15T07:01:00.000Z

Patch for Video class: #111
Now, I didn't notice any error in Playlist class. Just FYI, this class was recently patched, and fix hasn't landed to PyPI yet. This is why you are having this error. You can install latest version from here: pip install git+https://github.com/alexmercerind/youtube-search-python

Answer 14 · 2021-09-15T10:33:19.000Z

Closing, since error doesn't occour anymore. If it does, then comment here.

Answer 15 · 2021-09-15T17:22:22.000Z

I am having this same issue but with playlists

Traceback (most recent call last):
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\site-packages\youtubesearchpython\internal\extras.py", line 162, in __makeRequest
    response = urlopen(request, timeout=self.timeout)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 223, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 532, in open
    response = meth(req, response)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 642, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 570, in error
    return self._call_chain(*args)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 504, in _call_chain
    result = func(*args)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 650, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "video.pyw", line 62, in <module>
    playlist = Playlist(link1)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\site-packages\youtubesearchpython\extras.py", line 548, in __init__
    self.__playlist = PlaylistInternal(playlistLink, None, ResultMode.dict, self.timeout)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\site-packages\youtubesearchpython\internal\extras.py", line 136, in __init__
    statusCode = self.__makeRequest(playlistLink)
  File "C:\Users\arcti\AppData\Local\Programs\Python\Python36\lib\site-packages\youtubesearchpython\internal\extras.py", line 166, in __makeRequest
    raise Exception('ERROR: Could not make request.')
Exception: ERROR: Could not make request.

Answer 16 · 2021-09-15T18:22:54.000Z

As i said, fix hasnt landed to PyPI yet. You have to get latest version from git: pip install git+https://github.com/alexmercerind/youtube-search-python
I have tested everything in the morning, and it worked ok.
Please test latest release from git first.

Answer 17 · 2021-09-15T19:52:35.000Z

Awesome, that worked! Very much appreciated

Answer 18 · 2021-09-17T18:05:47.000Z

same fix is needed for the __future__ subpackage

Answer 19 · 2021-09-17T18:44:46.000Z

same fix is needed for the __future__ subpackage

One of next things from me is going to be a rewrite of synchronous and asynchronous packages (as part of #104), to extract core, so that everything should be easier to maintain. This is probably gonna happen next week. No breaking changes at the API, just easier maintaining. I will do it then, but if you want it ASAP you can always create a PR.

Thanks

Answer 20 · 2021-09-17T20:29:13.000Z

same fix is needed for the __future__ subpackage

One of next things from me is going to be a rewrite of synchronous and asynchronous packages (as part of #104), to extract core, so that everything should be easier to maintain. This is probably gonna happen next week. No breaking changes at the API, just easier maintaining. I will do it then, but if you want it ASAP you can always create a PR.

Thanks

Thanks a lot <3

Answer 21 · 2021-09-20T10:49:03.000Z

I have started with rewrite, and have extracted the core of this package. Now, asynchronous & synchronous functions in extras.py share code between themselves. So, __future__ subpackage is now fully working. This fix hasn't yet landed on main repository, since I have to make some improvements, so for now you can install my fork: pip install git+https://github.com/mytja/youtube-search-python