Perpendicular of a line in PHP

[evigra]

Good day friend.
How can I make a perpendicular of a line in PHP?
In JAVASCRIPT (gmaps)

`

var spherical = google.maps.geometry.spherical;

var F = new google.maps.LatLng(51.524, -0.099); 
var T = new google.maps.LatLng(51.531, -0.114); 

var myOptions = {
    zoom: 14,
    center: F,
    mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);

// Draw line
var segmentCoordinates = [F, T ];
var segment = new google.maps.Polyline({
    path: segmentCoordinates,
    geodesic: true,
    strokeColor: '#00FF00',
    strokeOpacity: 1.0,
    strokeWeight: 2,
    map: map
  });    

// Get direction of the segment
var heading = spherical.computeHeading(F, T);

var dist = 500; // distance in meters    
var A = spherical.computeOffset(F, dist, heading+90);
var B = spherical.computeOffset(F, dist, heading-90);
var perpendicularCoordinates = [A, B ];

var perpendicular = new google.maps.Polyline({
    path: perpendicularCoordinates,
    geodesic: true,
    strokeColor: '#FF0000',
    strokeOpacity: 1.0,
    strokeWeight: 2,
    map: map
  });    

`

[alexpechkarev]

Hi @evigra,

Thank you for your question.

This package has SphericalUtil class that can be used to obtain values for

// JavaScript
var heading = spherical.computeHeading(F, T);

var A = spherical.computeOffset(F, dist, heading+90);
var B = spherical.computeOffset(F, dist, heading-90);

// PHP
$distance = 500;
$from = ['lat' => 25.775, 'lng' => -80.190];
$to = ['lat' => 21.774, 'lng' => -80.190];
$heading = SphericalUtil ::computeHeading($from, $to);

$A = SphericalUtil::computeOffset($from, $distance, $heading+90);
$B = SphericalUtil ::computeOffset($to, $distance, $heading-90);

Haven't tried above code, but it should be not far from what you looking for.

Regards,
Alexander