Is there a way to define how types are written?
Closed this issue · 1 comments
Currently json-schema-to-typescript generates the following code:
export type Operator =
| "Equals"
| "NotEquals"
| "Contains"
| "NotContains"
| "EqualsOrGreaterThan"
| "EqualsOrLesserThan"
| "OneOf"
| "Empty"
| "NotEmpty";
// same for keys
// same for values
export interface Predicate {
key: Key;
operator: Operator;
values: Values;
}It is valid and working fine, however, I could not find a way to enumerate all the possible values of an operator for other operation. For instance, I would want to create a Record<Operator, string> to translate the Operator.
I want to avoid writing the following to make sure when my schema changes, the dictionnary changes too:
const translation = {
"Equals": "is equal to",
"NotEquals": "does not equal",
// and everything else is also done manually...
}The problem above is that I need to re-instanciate a new string for each operator.
Is there a way to do this in TypeScript or a way to change the json-schema-to-typescript output ?
I have been looking at this article which suggest to have something like:
export const OperatorValues = ['Equals', 'NotEquals'] as const;
type OperatorType = typeof OperatorValues[number]; Thanks for your input 🙏
You want to add an explicit type annotation to translation, to tell TypeScript that you expect it to have all the keys.
const translation: Record<Operator, string> = {
...