How we are handling -ve values by sum of mod value 10^9+7.
Opened this issue · 1 comments
abhik235 commented
if(sum < 0) {
sum = sum + mod;
}
I didn't get this part. However -ve value is also possible then if we add 10^9+7 it will become +ve which is wrong. Please clarify this.
FazeelUsmani commented
If you want to handle -ve values then you can perform
ans = (ans + MOD) % MOD
at the end