Adjacency Matrix: doc error for undirected graphs

[tesfabpel]

In the doc page for adjacency matrices there is an error for undirected graphs.
It says:

In the case of an undirected graph, the adjacency_matrix. class does not use a full V x V matrix but instead uses a lower triangle (the diagonal and below) since the matrix for an undirected graph is symmetric. This reduces the storage to (V²)/2. Figure 2 shows an adjacency matrix representation of an undirected graph.

In particular, This reduces the storage to (V²)/2 is wrong, since if you count the number of items in the Figure 2, you can see that there are 21 items for a graph of 6 vertices (instead of (6²)/2 = 36 / 2 = 18).

I believe the correct formula is (V² + V) / 2.

For n = 1: (1² + 1) / 2 = 2 / 2 = 1
For n = 2: (2² + 2) / 2 = 6 / 2 = 3
For n = 6: (6² + 6) / 2 = 42 / 2 = 21

[tesfabpel]

I've also created a small python script to test for the idea and it prints OK:

def count_by_formula(n):
    # if n is odd, `n*n + n` should be 
    # guaranteed to be even since
    # `n*n` should return again an odd number
    # and an odd + an odd makes an even
    # number. So dividing it by 2
    # produces an integer.
    
    return int((n*n + n) / 2)

def count_by_summing_rows(n):
    s = 0
    
    for i in range(n):
        s = s + i + 1
        
    return s

for n in range(100):
    test = count_by_formula(n)
    expected = count_by_summing_rows(n)
    
    print(n, ':', test, expected)
    
    if test != expected:
        print('Error')
        raise n

print('OK')

~$ python boost-graph-doc-matrix-bug.py
0 : 0 0
1 : 1 1
2 : 3 3
3 : 6 6
4 : 10 10
5 : 15 15
6 : 21 21
7 : 28 28
8 : 36 36
9 : 45 45
10 : 55 55
[...]
OK

[valiko-ua]

You are correct if we are talking about exact numbers, but when analyzing an algorithm complexity and memory requirements only the biggest term is of interest. Look for Big O notation for more info.

[tesfabpel]

Ah I see, I thought it was an exact number and not Big-O notation and it wasn't explicitly specified (it also says For a graph with V vertices, a V x V matrix is used in the paragraph above so I thought there was a mistake).

Also, doesn't O(n^2/2) simplify into O(n^2) in Big-O (since the /2 part is a constant)?

Anyway, thank you! If the documentation is written as intended, this issue can be closed according to me.

[valiko-ua]

Also, doesn't O(n^2/2) simplify into O(n^2) in Big-O (since the /2 part is a constant)?

You are correct here too. Maybe due to this reason the author didn't use Big-O.
I'm not the author of those pages, just express my opinion.