Unable to curse __call__
MrFizzyBubbs opened this issue · 0 comments
MrFizzyBubbs commented
Attempting to curse the __call__
method results in a KeyError. Minimum working example below.
def wrap(func):
def wrapped(*args, **kwargs):
print("intercepted")
return func(*args, **kwargs)
return wrapped
curse(int, "__call__", wrap(int.__call__))