Convert Conjugate gradient to single precision

Question

Convert Conjugate gradient to single precision

Closed this issue 2 years ago · 3 comments

We need to copy the device float array x2_f into the managed double array x2. Because this is CUDA a simple x2_f[i]=(float)x2[i] won't cut it. One option is to change x2_f to be managed too. Need to see where the managed array is used though and who that'll affect memory performance.

Answer 1 · 2022-12-20T20:26:50.000Z

So far so good for congradq. Still need to work on congradp

Answer 2 · 2022-12-22T15:53:25.000Z

Removing bug label for now as Congradp does calculate correctly in DP

Answer 3 · 2023-01-03T12:34:07.000Z

We may need to look at the CUDA version of Congradp again at a later date