can not read R["R.version.string"] as string
Closed this issue · 2 comments
josp70 commented
Hi, I'm trying to read the value of R.version.string using the operator []. As a result an exception is thrown. Instead, with R.parseEval("R.version.string") is OK. Below is the example rinside_sample0.cpp modified showing the issue.
#include <RInside.h> // for the embedded R via RInside
int main(int argc, char *argv[]) {
RInside R(argc, argv); // create an embedded R instance
try {
std::string versionKO = R["R.version.string"];
} catch(std::exception& ex) {
std::cerr << "Exception caught: " << ex.what() << std::endl;
} catch(...) {
std::cerr << "Unknown exception caught" << std::endl;
}
std::string versionOK = R.parseEval("R.version.string");
std::cout << versionOK << std::endl;
R["txt"] = "Hello, world!\n"; // assign a char* (string) to 'txt'
R.parseEvalQ("cat(txt)"); // eval the init string, ignoring any returns
exit(0);
}
eddelbuettel commented
To a first approximation, you need to parse and eval a valid R expression. As such, your approach using [ ... ]
is just wrong -- that is not how it works.
The second approach is correct, and you say it works. So I am closing this -- there is no issue here.
josp70 commented
I found another way without parsing and evaluating an R expression:
Rcpp::Environment baseEnv("package:base");
std::string versionR = baseEnv["R.version.string"];