Inherit options types set in `Base.defaults()`
gr2m opened this issue · 3 comments
gr2m commented
Example
const BaseWithDefaults = Base.defaults({ parentOption: "value" })
const baseWithDefaults = new BaseWithDefaults({ childOption: "value" })
baseWithDefaults.options.childOption // should be typed as string
baseWithDefaults.options.parentOption // should be typed as string
I don't know if this is even possible. Any idea?
Here is a playground with the full source code to mess around with
gr2m commented
Here is simpler version of Base
with only the static defaults
method and a TOptions
type parameter: playground. That's how far I got so far
gr2m commented
@jacobwgillespie found a possible solution: playground (via TypeScript's Community Discord)
github-actions commented
🎉 This issue has been resolved in version 2.1.0 🎉
The release is available on:
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