Cannot GET /d-solo/....

[OJthe123]

Hi.

I tried the renderer docker container with grafana 11.1.0 docker image.
But when I try to render an image with

http://10.xxx.1.xxx:8081/d-solo/edn2390pup6o0c/tp?orgId=1&from=1716885345846&to=1716885811742&panelId=1

I get the error in browser:

Cannot GET /d-solo/edn2390pup6o0c/tp

and in docker logs
{"level":"error","message":"::ffff:10.xxx.1.xxx - - [24/Jun/2024:05:55:04 +0000] \"GET /d-solo/edn2390pup6o0c/tp?orgId=1&from=1716885345846&to=1716885811742&panelId=1 HTTP/1.1\" 404 163 \"-\" \"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36 Edg/125.0.0.0\"\n"}

What am I doing wrong?

here are the parts in my docker compose

grafana:
   image: grafana/grafana-enterprise:main
   container_name: grafana
   restart: unless-stopped
   ports:
     - '3000:3000'
   volumes:
     - grafana-storage:/var/lib/grafana
     - type: bind
       source: ./grafana-provisioning/
       target: /etc/grafana/provisioning
   depends_on:
     - influxdb
   environment:
     - GF_SECURITY_ADMIN_USER=$GRAFANA_USERNAME
     - GF_SECURITY_ADMIN_PASSWORD=$GRAFANA_PASSWORD
     - GF_SECURITY_ALLOW_EMBEDDING=$GRAFANA_ALLOW_EMBEDDING
     - GF_AUTH_ANONYMOUS_ENABLED=$GRAFANA_AUTH_ANONYMOUS_ENABLED
     - GF_AUTH_ANONYMOUS_ORG_NAME=$GRAFANA_AUTH_ANONYMOUS_ORG_NAME
     - DOCKER_INFLUXDB_INIT_ADMIN_TOKEN=$DOCKER_INFLUXDB_INIT_ADMIN_TOKEN
     - GF_RENDERING_SERVER_URL=http://renderer:8081/render
     - GF_RENDERING_CALLBACK_URL=http://grafana:3000
     - GF_LOG_FILTERS=rendering:debug
     - GF_RENDERING_RENDERER_TOKEN=$GRAFANA_RENDERER_TOKEN
   networks:
       - default

 renderer:
   image: grafana/grafana-image-renderer:latest
   ports:
     - 8081:8081
   environment:
     - AUTH_TOKEN=$GRAFANA_RENDERER_TOKEN
   networks:
     - default

[OJthe123]

Sorry....please ignore this...
I just found the solution...by click on the menu of a panel and Share->Link->Dircet Link rendered image (at the bottom), I can see the right URL and it renders perfectly