[js] 第272天 用不同的方法改装下面的代码,使它的结果输出为0-4[代码]
Opened this issue · 7 comments
haizhilin2013 commented
第272天 用不同的方法改装下面的代码,使它的结果输出为0-4[代码]
for (var i = 0; i < 5; i++){
setTimeout(() => {
console.log(i);
}, 1000)
}
HCLQ commented
for (let i = 0; i < 5; i++){ setTimeout(() => { console.log(i); }, 1000) }
forever-z-133 commented
使用 setTimeout 的第三个入参(有兼容问题),使用自运行函数,抽离成新方法
forever-z-133 commented
存个数组延时后使用 shift 获取
Jingce-lu commented
补充两个
for (var i = 0; i < 5; i++) {
setTimeout(console.log(i), 1000)
}
for (var i = 0; i < 5; i++) {
setTimeout(eval('console.log(i)'), 1000)
}
yini0223 commented
for(var i = 0; i < 5; i++){
((j) => {
setTimeout(() => {
console.log(j)
},1000)
})(i);
}
renqi1996 commented
let output = (i) => {
return new Promise(resolve => {
setTimeout(() => {
console.log(i)
resolve()
},1000)
})
}
(async function () {
for (var i = 0; i < 5;i++) {
await output(i)
}
})()
let task = []
let output = (i) => {
return new Promise(resolve => {
setTimeout(() => {
console.log(i)
},1000*i)
})
}
for (var i = 0; i < 5;i++) {
task.push(output(i))
}
Promise.all(task)
xiaoqiangz commented
for(var i=0;i<5;i++) {
(function(n){
setTimeout( ()=> console.log(n), 1000)
}(i))
}
for(let i=0;i<5;i++) {
setTimeout( ()=> console.log(i), 1000)
}