reverse-integer more easy understand

[zhoupro]

#include
class Solution {
public:
int reverse(int x) {
int n;
long ret = 0; // in case overflow
while(x != 0){
n = x % 10;
ret = ret * 10 + n;
if(ret > INT_MAX || ret < INT_MIN){
return 0;
}
x = x / 10;
}
return ret;
}
};