ByteLevelBPETokenizer output seems weird
seyyaw opened this issue · 2 comments
I use the ByteLevelBPETokenizer
to train a custom tokenizer for Amharic language (less-resource language).
tokenizer = ByteLevelBPETokenizer(lowercase=False)
tokenizer.train(files=paths, vocab_size=32000, min_frequency=3, special_tokens=[
"<s>",
"<pad>",
"</s>",
"<unk>",
"<mask>",
])
The merge.txt and vocab.json files I obtained are now not human readable.
áĪ ħ
áĪ °
ĠáĬ¥ áĬķ
ĠáĬ ¨
Ġáĭ Ń
áĬ Ń
ĠáĪ Ī
áį į
Also the encoding results in the same unreadable output
output = tokenizer.encode("አበበ በሶ በላ። ጫላ ጩቤ ጨበጠ፡፡")
print(output.ids, output.tokens, output.offsets)
>>>[0, 319, 5739, 2883, 4037, 303, 1631, 299, 5173, 506, 748, 11918, 363, 2] ['<s>', 'áĬł', 'áīłáīł', 'ĠáīłáĪ¶', 'ĠáīłáĪĭ', 'áį¢', 'ĠáĮ«', 'áĪĭ', 'ĠáĮ©', 'áī¤', 'ĠáĮ¨', 'áīłáĮł', 'áį¡áį¡', '</s>'] [(0, 0), (0, 3), (3, 9), (9, 16), (16, 23), (23, 26), (26, 30), (30, 33), (33, 37), (37, 40), (40, 44), (44, 50), (50, 56), (0, 0)]
Is this the expected behavior? I will later use this to train a RoberTa model using the run_language_modeling.py
script.
Thanks
I also have a similar issue with Persian texts.
TLDR; This is how the byte-level BPE works. Main advantages are:
- Smaller vocabularies
- No unknown token
This is totally expected behavior. The byte-level BPE converts all the Unicode code points into multiple byte-level characters:
- Each Unicode code point is decomposed into bytes (1 byte for ASCII characters, and up to 4 bytes for UTF-8 Unicode code points)
- Each byte value gets a "visible" character assigned to it from the beginning of the Unicode table. This is especially important because there are a lot of control characters, so we can't just have a simple mapping ASCII Table character <-> byte value. So some characters get other representations, like for example the white space
U+0020
becomesĠ
.
The purpose is, by doing so, you end up with an initial alphabet of 256 tokens. These 256 tokens can then be merged together to represent any other token in the vocabulary. This results in smaller vocabularies, that won't ever need an "unknown" token.