Closed this issue 2 years ago · 1 comments
mod 6 remaining 0, 5 -> 0 remaining 1, 4 -> 1 remaining 2, 3 -> 2
((5-0)^2 + (5-5)^2) / 8 = 3 ((5-1)^2 + (5-4)^2) / 8 = 2 ((5-2)^2 + (5-3)^2) /8 = 1