texmath converts $\ddot{q}$ to $q^(̈)$ from LaTeX to Typst

[Kreijstal]

Your notation doesn't render that well, it renders the parenthesis with the double dots.
However the correct move in this should be $dot.double(q)$
\dddot is also dot.triple
and \ddddot is dot.quad

[jgm]

\ddot{q} parses as

[ EOver False (EIdentifier "q") (ESymbol Accent "\776") ]

The problem is that dot.double is \168 (scraped from the typst documentation on symbols).

776 = Combining Diaeresis
168 = Diaeresis

You'll note we don't have trouble with \dddot, just \ddot, and this is why.

In typst-symbols, dot.triple is

8411 - combining three dots above

In my opinion, it would make sense for dot.double and dot.triple both to be mapped to characters with similar unicode properties -- hence 776.

cc @laurmaedje

In the mean time, though, we can probably just add some code to treat 776 as 168 for purpose of typst symbol lookup.

[jgm]

I've fixed this with the workaround. @laurmaedje I'm really not sure about the character mapping issue -- you probably know more than I do about this -- but I thought I'd raise the issue.

[laurmaedje]

If I recall correctly, we did it this way because we generally wanted the non-combining character as the default for the symbol (e.g. tilde is a normal tilde, not a combining one and diaresis/dot.double is the same), but the triple dot only exists in combining form. I'm not 100% sure though.