Starting ulogme at login
glung opened this issue · 3 comments
Hello,
I am not too sure where to put the instructions or the code for starting ulogme at run time. I think though it would be useful for others. I can contribute but need some guidance.
Cheers
on macosx, you need to create the file ulogme-launcher.plist
in ~/Library/LaunchAgents/
<plist version="1.0">
<dict>
<key>Label</key>
<string>ulogme-daemon</string>
<key>RunAtLoad</key>
<true />
<key>Program</key>
<string>/Users/<PATH>/launch_ulogme.sh</string>
</dict>
</plist>
launch_ulogme.sh
contains
#!/bin/sh
(cd <{PATH_TO_ULOGME> && ./ulogme.sh)
Then, run :
launchctl load ~/Library/LaunchAgents/ulogme-launcher.plist
I tried this, and noticed that the script stopped recording keyfreq.
Once I run the script directly, with launch_ulogme.sh, the keys are recorded.
Didn't find a solution so far.
The problem occurs because the keyfreq recording requires root access (at least on linux). For me, I solved this with the following modification of the ulogme.sh
script (please note, this code is for Bash under Linux, I have no Mac OS to check it):
# Assume Linux
DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
pushd "${DIR}"
echo "" > ./ulogme.log
until [ "$(pgrep -fca 'keyfreq')" -gt 0 ]
do
gksudo -D <homedir>/.config/autostart/ulogme.desktop ./keyfreq.sh &
sleep 10
echo "trying to start keyfreq" >> ./ulogme.log
started_count=$(pgrep -fca "keyfreq")
echo "started_count = ${started_count}"
done
until [ "$(pgrep -fca 'logactivewin')" -gt 0 ]
do
./logactivewin.sh &
echo "trying to start logactivewin" >> ./ulogme.log
started_count=$(pgrep -fca "logactivewin")
echo "started_count = ${started_count}"
done
until [ "$(pgrep -fca 'ulogme_serve')" -gt 0 ]
do
python ./ulogme_serve.py &> /dev/null &
echo "trying to start ulogme_serve" >> ./ulogme.log
started_count=$(pgrep -fca "ulogme_serve")
echo "started_count = ${started_count}"
done
echo "all routines started"
popd