interface 注解遇到 `operator` 关键字生成错误
onXoot opened this issue · 1 comments
onXoot commented
ktorm-ksp version: 1.0.0-RC3
ktorm version: 3.5.0
code
@org.ktorm.ksp.api.Table("test")
interface TestOperator: org.ktorm.entity.Entity<TestOperator> {
@org.ktorm.ksp.api.PrimaryKey
var id: Long
var operator: String
}
自动生成的代码
@Suppress("FunctionName")
public fun TestOperator(id: Long? = undefined(), operator_: String = undefined()): TestOperator {
val entity = Entity.create<TestOperator>()
if (id !== undefined<Long?>()) {
entity.id = id ?: error("`entity` should not be null.")
}
if (operator !== undefined<String>()) {
entity.operator = operator
}
return entity
}
public fun TestOperator.copy(id: Long? = undefined(), operator_: String = undefined()):
TestOperator {
val entity = this.copy()
if (id !== undefined<Long?>()) {
entity.id = id ?: error("`entity` should not be null.")
}
if (operator !== undefined<String>()) {
entity.operator = operator
}
return entity
}
operator
在参数上自动加了个下划线,但是下面使用的时候没加 导致编译失败
使用实体类形式可以编译成功
vincentlauvlwj commented
好的,谢谢