怎么把SentText 改成异步的啊！

[Xuzan9396]

我是通过com注入

class MyWeChatEventSink(wxRobot.WeChatEventSink):
    def __init__(self, wxBot: wxRobot.WeChatRobot):
        self.wxBot = wxBot

    def send_text(self, sender, text):  # 我需要改成异步
        self.wxBot.SendText(sender, text)
        time.sleep(20)  # 睡眠5秒

    def OnGetMessageEvent(self, msg):
        msg = json.loads(msg[0])
        print("类型:" + str(type(msg)))
        print(msg )
        if msg is not None:
            print("消息内容:" + str(msg.get('message')))
            message = msg.get('message')
            if message is None:
                return

            content = str(message).strip()
            sender = msg.get('sender')
            isSendMsg = msg.get('isSendMsg')

            if isSendMsg is None or isSendMsg == 1:
                return

            if content != "" and sender == "xxxxx" and isSendMsg == 0:
                if self.wxBot is not None:
                    self.send_text(sender, "hello world")


if __name__ == '__main__':
    pid_list = wxRobot.get_wechat_pid_list()
    wx = WeChatRobot(pid_list[0])
    try:
        wx.StartService()
        wx.StartReceiveMessage()
        eventSink = MyWeChatEventSink(wx)
        wxRobot.register_msg_event(pid_list[0],eventSink)

    except Exception as e:
        print(e)
        wx.StopService()

[cheungchazz]

你这个time.sleep(20)就阻塞线程了

[Xuzan9396]

不是的，我是想异步处理消息，time.sleep(20) 是我模拟业务处理的场景

[hd5870m]

我改过其他人的hook程序，可以实现