Require matching number of hashes for Rust-style raw strings?

[AshtonSnapp]

Hello,

Is there any way to create a regular expression that requires two matching groups to match each other? Specifically, I want to create a regex that would match a Rust-style raw string (r(#*)"..."(#*) where the two (#*) groups have to have the same number of #s). Right now my regex is r#"(?:[^("#r)])"#r (I want a matching r on each side as well...), but that will only match exactly one # on each side, no less, no more.

If there is a way to do this, please let me know. If there is no way to do this, will there be a way in future versions or will I be stuck with single # raw strings?

[jeertmans]

Hello, you should have a look at #351, as I think this is a duplicate of this.

For the group matching part, this is impossible to do that with pure regexes I am afraid.

[AshtonSnapp]

Alright. looks like I'll just have to use r#"..."#r for the mean while. Thanks for letting me know.