39.Combination Sum
Opened this issue · 0 comments
niuworld commented
Question:
Given a set of candidate numbers (C) and a target number (T), find >all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of >times.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending >order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7 and target 7,
A solution set is:
[7]
[2, 2, 3]
Solution:
backtracking
class Solution {
public:
vector<int>res;
vector<vector<int>>finalres;
void helper(vector<int> & ca, int tar ,vector<int>&re ,vector<vector<int>>&final ,int begin){
if ( tar == 0){
final.push_back(re);
return;
}
for( int i = begin; i <= ca.size() - 1 && ca[i] <= tar; ++i){
re.push_back(ca[i]);
helper(ca, tar - ca[i], re , final, i);
re.pop_back();
}
}
vector<vector<int>> combinationSum(vector<int>& candidates, int target) {
sort(candidates.begin(), candidates.end());
helper(candidates, target , res , finalres , 0);
return finalres;
}
};