Bisimulation: Mention satisfaction of TxConstraints
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omelkonian commented
- For soundness, this is trivial (since we are using
constrain tx= tx
), which contains the proof(verifyTx tx tx≡ ≡ true)
.
Closed this issue · 0 comments
constrain tx= tx
), which contains the proof (verifyTx tx tx≡ ≡ true)
.