本地debug，报pydantic的KeyError: 'UUID'
fenglvming opened this issue · 3 comments
fenglvming commented
启动方式，本地python app/main.py
File "/opt/anaconda3/envs/labelllm/lib/python3.11/site-packages/pydantic/_internal/_core_utils.py", line 197, in walk
return f(schema, self._walk)
^^^^^^^^^^^^^^^^^^^^^
File "/opt/anaconda3/envs/labelllm/lib/python3.11/site-packages/pydantic/_internal/_core_utils.py", line 441, in collect_refs
return recurse(s, collect_refs)
^^^^^^^^^^^^^^^^^^^^^^^^
File "/opt/anaconda3/envs/labelllm/lib/python3.11/site-packages/pydantic/_internal/_core_utils.py", line 200, in _walk
schema = self._schema_type_to_method[schema['type']](schema.copy(), f)
~~~~~~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^
KeyError: 'UUID'
lacia-hIE commented
可以提供更多有效信息吗，例如完整的启动步骤
ZhongQiyu commented
UUID是百度的标记算法, 你看一下怎么弄