Arpeggio inversion
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pinobatch commented
Once arpeggios have names, the next step is to derive names for a chord's first inversion and second inversion. These move notes from the bottom of a chord to the top.
To calculate an inversion of an arpeggio whose low nibble is zero, such as 70
, subtract it from C0
. This preserves the ratio for 50:50 2-note arpeggios. Otherwise:
- Calculate all three nibbles of the arpeggio.
- Replace all 0 nibbles with C.
- Subtract the nibble with the lowest value from all nibbles.
- Rotate left by nibbles until a 0 is in the top position, and drop it.
Three worked examples:
Arp 3nib Cify Sub Rot
47 047 C47 803 038
07 007 CC7 550 055
77 077 C77 500 005
Inserting /1
or /2
after an arpeggio should perform inversion once or twice.
orelative
# this
EN47 c4. EN47/1 e EN47/1 g2.
# does the same as this
EN47 c4. EN38 e EN59 g2.