pjpjq/nameof

A header only C++ library provides nameof() macro to obtain the std::string name of a variable, type, or member. It works like nameof() in C#

nameof

A header only C++ library provides nameof() macro to obtain the std::string name of a variable, type, or member.

It works like nameof() in C#.

nameof() accepts expression which should be compilable. If expression is compilable but not correspond expressions which shown below, the std::logic_error exception will be thrown.

Usage

First you should download and include nameof.h file.

    #include "nameof.h"

You can get the name of a variable.

    int bar;
    std::string name = nameof(bar); // "bar"

You can get the name of a function. You should use an ampersand (&).

    void foo();
    std::string name = nameof(&foo); // "foo"

You can get the name of an enum element.

    enum Foo {Bar};
    std::string name = nameof(Foo::Bar); // "Bar"

You can get the name of a class or a struct.

    class Foo {};
    std::string name = nameof(Foo); // "Foo"

You can get the name of a method. Do not forget to add an ampersand (&).

    struct Foo { int bar(); };
    std::string name = nameof(&Foo::bar); // "bar"

You can get the name of a class or struct field.

    struct Foo { int bar; };
    std::string name = nameof(Foo::bar); // "bar"

You can get the name of a field of an object.

    struct Foo { int bar; };
    Foo foo;
    std::string name = nameof(foo.bar); // "bar"

You can use ::, -> and . operators with any depth of nesting of entities and with namespaces.

    struct Foo1
    {
        struct Foo2
        {
            Foo1* foo1;
        };

        Foo1* foo1;
        Foo2 foo2;
    };
    std::string name = nameof(Foo1::foo1->foo2.foo1); // "foo1"

Testing

Dependencies

• Boost

Start

    cd test
    make

Good luck!