Get shipping service name by its code
Opened this issue · 2 comments
It would be great if I could get service name by its code with something like this:
def get_service_name(service_code):
"""
Given a service code, return the human-readable name for
that service
@return: string on success or False
"""
return SHIPPING_SERVICES_NAMES.get(service_code, service_code)
I don't immediately object to this. What is the use case? For example, when requesting tracking information, the return XML from UPS gives a human-readable description of the shipping type in TrackResponse.Shipment.Service.Description
. Would it be sufficient to expose that? Or is the goal to get a list of all supported types? In that case, would it just return the existing SHIPPING_SERVICES
dict?
Well, the existing dict
SHIPPING_SERVICES = {
'1dayair': '01', # Next Day Air
'2dayair': '02', # 2nd Day Air
'ground': '03', # Ground
'express': '07', # Express
'worldwide_expedited': '08', # Expedited
'standard': '11', # UPS Standard
'3_day_select': '12', # 3 Day Select
'next_day_air_saver': '13', # Next Day Air Saver
'next_day_air_early_am': '14', # Next Day Air Early AM
'express_plus': '54', # Express Plus
'2nd_day_air_am': '59', # 2nd Day Air A.M.
'ups_saver': '65', # UPS Saver.
'ups_today_standard': '82', # UPS Today Standard
'ups_today_dedicated_courier': '83', # UPS Today Dedicated Courier
'ups_today_intercity': '84', # UPS Today Intercity
'ups_today_express': '85', # UPS Today Express
'ups_today_express_saver': '86', # UPS Today Express Saver.
}
returns only ID of each service. I would like to get its name. For example: get_service_name('1dayair')
or get_service_name('01')
would return 'Next Day Air'
. I am also trying to get rates for a giving package information for all available shipping services without confirming the created shipping. Is it possible?