High Value Palindrome
prabaprakash opened this issue · 1 comments
prabaprakash commented
Algo
#include <bits/stdc++.h>
using namespace std;
string richieRich(string s, int n, int k){
int lives=k;
vector<bool> mod(n,false);
string temp(s);
for (int i=0;i<n/2;i++)
{
if (temp[i]!=temp[n-i-1]) {mod[i]=true;lives--;}
if (temp[i]<temp[n-i-1]) temp[i]=temp[n-i-1]; else if (temp[i]>temp[n-i-1]) temp[n-i-1]=temp[i];
if (lives<0) return "-1";
}
int j=0;
while ((lives>0)&&(j<n/2))
{
if (temp[j]!='9'){
if (mod[j]) lives++;
if (lives>1) {temp[j]='9';temp[n-j-1]='9'; lives-=2;}
}
j++;
}
if (n%2==1) {if (lives>0) temp[n/2]='9';}
return temp;
}
int main() {
int n;
cin >> n;
int k;
cin >> k;
string s;
cin >> s;
string result = richieRich(s, n, k);
cout << result << endl;
return 0;
}prabaprakash commented
js solution
function highestValuePalindrome(s, n, k) {
let lives = k;
let mod = new Array(n).fill(false);
let temp = s.split('');
for (let i = 0; i < n / 2; i++) {
let j = n - i - 1;
if (temp[i] != temp[j]) {
mod[i] = true;
lives--;
}
if (temp[i] < temp[j])
temp[i] = temp[j];
else if (temp[i] > temp[j])
temp[j] = temp[i];
if (lives < 0)
return "-1";
}
let j = 0;
while ((lives > 0) && (j < n / 2)) {
if (temp[j] != '9') {
if (mod[j])
lives++;
if (lives > 1) {
temp[j] = '9';
temp[n - j - 1] = '9';
lives -= 2;
}
}
j++;
}
if (n % 2 == 1) {
if (lives > 0)
temp[Math.floor(n / 2)] = '9';
}
return temp.join('');
}