PermissionError: [WinError 5] Access is denied - python - pytesseract.image_to_string
jaydattpatel opened this issue · 2 comments
I tried to run image to string convert program in python using pytesseract. I am using VS code with Jupyter Extension and Python 3.12.0 installed. I am facing error in pytesseract.image_to_string......
`from PIL import Image
import pytesseract
pytesseract.pytesseract.tesseract_cmd = r'C:\Users\KP\AppData\Local\Programs\Python\Python312\Lib\site-packages\pytesseract'
image = Image.open("readonly/text.png")
text = pytesseract.image_to_string(image)
print(text)
PermissionError Traceback (most recent call last)
c:\Users\KP\Downloads\Python Project pillow, tesseract, and opencv\Week-2\Jupitor files\module_2.ipynb Cell 9 line 2
1 # One last thing to mention - the image_to_string() function takes in an "image", but the docs don't
2 # really describe what this image is underneath. Is it a string to an image file? A PILLOW image?
3 # Something else?
(...)
27 #
28 # Ok, lets try and run tesseract on this image
---> 29 text = pytesseract.image_to_string(image)
30 print(text)
File c:\Users\KP\AppData\Local\Programs\Python\Python312\Lib\site-packages\pytesseract\pytesseract.py:423, in image_to_string(image, lang, config, nice, output_type, timeout)
418 """
419 Returns the result of a Tesseract OCR run on the provided image to string
420 """
421 args = [image, 'txt', lang, config, nice, timeout]
--> 423 return {
424 Output.BYTES: lambda: run_and_get_output(*(args + [True])),
425 Output.DICT: lambda: {'text': run_and_get_output(*args)},
426 Output.STRING: lambda: run_and_get_output(*args),
427 }output_type
File c:\Users\KP\AppData\Local\Programs\Python\Python312\Lib\site-packages\pytesseract\pytesseract.py:426, in image_to_string..()
418 """
...
898 cmd_line = patch_arg_str_win(cmd_line)
899 send_process_created_message()
--> 901 return getattr(_subprocess, original_name)(app_name, cmd_line, *args)
PermissionError: [WinError 5] Access is denied`