Unable to (q)uit during loop after (s)tep
Closed this issue · 1 comments
GoogleCodeExporter commented
What steps will reproduce the problem?
1. run your program as normal
2. (s)tep a chunk of code
3. try and (q)uit will only allow to be done so after each chunk has been
stepped through within the loop() function
What is the expected output? What do you see instead?
I imagine that (q)uit should exit on demand without requirement to step through
the rest of the loop().
What version of the product are you using? On what operating system?
0.9.3
Please provide any additional information below.
Original issue reported on code.google.com by greyhatm...@gmail.com
on 24 Nov 2011 at 9:17
GoogleCodeExporter commented
This is working as designed, i.e. quit command "q" is only possible to execute
when a loop is completed. So when stepping ("s"), complete the loop with
command "r" and then quit. This is could be improved in a future version.
Original comment by benny.sa...@gmail.com
on 24 Nov 2011 at 10:01
- Changed state: WontFix
- Added labels: Type-Enhancement
- Removed labels: Type-Defect