format code fail, if there is an async function

Question

wugifer opened this issue 3 years ago · 5 comments

I wrote this:

fn                  test() {
    let a=1;
}

after formatted, I got this:

fn test() {
    let a = 1;
}

that is ok.

but when I wrote this:

async fn                  test() {
    let a=1;
}

fn test2           (){}

after formatted, nothing happen.

version: rust-analyzer v0.3.1301

Answer 1 · 2022-11-28T10:35:37.000Z

rustup 1.24.3 (ce5817a94 2021-05-31)

Answer 2 · 2022-11-28T10:41:41.000Z

rustfmt 1.4.38-stable (db9d1b20 2022-01-20)

Answer 3 · 2022-11-28T10:47:02.000Z

Cargo.toml:

[package]
edition = "2021"

Answer 4 · 2022-11-28T10:52:43.000Z

add edition = "2018" in rustfmt.toml, done

Answer 5 · 2022-11-28T13:08:55.000Z

Please report issues in rust-lang/rust-analyzer in the future. This repo is only for the rust-analyzer website, https://rust-analyzer.github.io/.