std::function and self
joeroback opened this issue · 3 comments
joeroback commented
I have a callback that get's bound in lua and from c++ I'd like to invoke that, but self
is always nil and I am not sure how to access self
as the lua table, not the Client*
C++ object...
local client = require 'client'
local view = {}
function view:onConnect()
self.connected = true
end
function view:create()
client:onConnect(self.onConnect)
end
m["Client"].setClass(
UserdataMetatable<Client>()
.addStaticFunction("onConnect", [](Client* self, const std::function<void(void)>& connectFn)
{
connectFn();
})
);
Is this possible with kaguya?
Thanks!
joeroback commented
similar example...
#include <kaguya/kaguya.hpp>
#include <cstdio>
typedef void (*OnConnectFn)(void);
void somefunction(const std::function<void()>& fn)
{
fn();
}
extern "C" int luaopen_fn(lua_State *L)
{
kaguya::State state(L);
kaguya::LuaTable module = state.newTable();
module["onConnect"] = kaguya::function(somefunction);
return module.push();
}
local fn = require 'fn'
local view = {}
function view:onConnect()
print('onConnect', self)
end
function view:main()
print('main', self)
print('fn', fn)
fn.onConnect(self.onConnect)
end
view:main()
joeroback commented
I've also tried LuaFunction
but no luck having self != nil
joeroback commented
this hack seems to work..
#include <kaguya/kaguya.hpp>
#include <cstdio>
typedef void (*OnConnectFn)(void);
void somefunction(kaguya::LuaFunction fn, kaguya::LuaTable self)
{
fn(self);
}
extern "C" int luaopen_fn(lua_State *L)
{
kaguya::State state(L);
kaguya::LuaTable module = state.newTable();
module["onConnect"] = kaguya::function(somefunction);
return module.push();
}
local fn = require 'fn'
local view = {}
function view:onConnect()
print('onConnect', self)
if self then
print('onConnect.data', self.data)
end
end
function view:main()
self.data = 'foobar'
print('main', self)
print('fn', fn)
fn.onConnect(view.onConnect, self)
end
view:main()
view:onConnect()
my manually passing self
lua table around...