Keyless variable in implicit object

Question

vendethiel opened this issue 9 years ago · 6 comments

We have {a} in the case of an explicit object, but I don't quite seem to remember a feature that'd allow this kind of thing to be simplified:

a =
  b: b
  # since we have:
  ...: c

Answer 1 · 2016-02-17T14:31:21.000Z

If you must:

a =
   ...: {b}

Answer 2 · 2016-02-17T16:16:47.000Z

Hm, thanks. Would you be interested in supporting it, or not at all?

Answer 3 · 2016-02-17T19:59:11.000Z

Support what?

Answer 4 · 2016-02-17T20:24:58.000Z

a single-variable variation

Answer 5 · 2016-02-17T21:21:46.000Z

But how? You can't blindly consume non-properties into a braceless object.

E.g. f p: q, g() wants to be f({p: q}, g()), not f({p: q, g: g}()).

Answer 6 · 2016-02-19T14:19:07.000Z

no, not blindly. I was thinking of some syntax, like *: a, but this might just be good enough.