Help reproducing c's XXH64

[jorgecarleitao]

given this program,

#define XXH_INLINE_ALL
#include "xxhash.h"
#include <stdlib.h>
#include <stdio.h>
int main()
{
    char* src = (char*) malloc(32);
    const int N = 32;
    for (int i = 0; i < N; i++) {
        src[i] = (char) i;
    }

    for (int i = 0; i <= 4; i++) {
       printf("%lldL,\n", (long long) XXH64(src, i, 0));
    }
}

I get

-1205034819632174695L,
-1642502924627794072L,
5216751715308240086L,
-1889335612763511331L,
-13835840860730338L,

however,

this one

use std::hash::Hash;

fn main() {
    let mut data = [0u8; 32];
    for i in 0..32 {
        data[i] = i as u8;
    }

    for i in 0..=4 {
        let mut hasher = twox_hash::xxh3::Hash64::with_seed(0);
        data[..i].hash(&mut hasher);
        let hash = hasher.finish();
        println!("{}", hash as i64);
    }
}

I am getting

1283693310379569971
-639235051960594343
5951188477818819634
8310689630395635833
-3146810259156790514

is there something I am doing incorrectly? I am trying to reproduce a result and got stuck here.

[jorgecarleitao]

the issue is that xxh3 is not XXH64, they are different hashes.