Double free in termination-recursive-malloc/chunk3.i
tautschnig opened this issue · 1 comments
The task is marked termination:true, but I don't know how to interpret this in presence of undefined behaviour, which is caused by the following lines:
These two calls to free
amount to a double-free, because the (tail-recursive) procedure chunk
sets the two pointers to the same value:
There is no case where those two pointers don't have the same value, because chunk
will perform at least one recursive call.
I can confirm the invalid free in this benchmark.
The task is marked termination:true, but I don't know how to interpret this in presence of undefined behaviour
@tautschnig I think that it was agreed in the past that benchmarks that contain undefined behavior (that is, the benchmark is false(def-behavior) or false(valid-deref) or false(valid-free)), then it should not have any other label than the "undefined" one.