dist creates folder

[fbacker]

.pipe(gulp.dest('./build/config.js'))

this will create a folder called config.js and it that place the file config.js
how to specify the output file? Want to do something like this

 gulp.src(["./src/store/config.default.js"]) 
    .pipe(replace('#SERVER', 'test'))
    .pipe(gulp.dest('./src/store/config.js'))

[fbacker]

sorry, my bad. New to gulp.
Added gulp-concat and now it works

 gulp.src("./src/store/config.default.js") 
    .pipe(replace('#SERVER', 'test'))
    .pipe(concat('config.js'))
    .pipe(gulp.dest('./src/store/'));

[tomaszczechowski]

Great that you found solution.
If you don't mind please rate project 😄