Can my wheel stop on more than one preselected segment?

[eddytele]

Hello,

I would like my wheel to stop on more than one of any preselected segments e.g segment 4, 7, 9, 10 only. Is it possible? Have I tried the code below in vain. I have tested with 'or', 'and' javascript functions but the wheel only stops on one segment. Please help.

// Function with formula to work out stopAngle before spinning animation.
// Called from Click of the Spin button.

function calculatePrize()
{
// This formula always makes the wheel stop somewhere inside prizes at least
// 1 degree away from the start and end edges of the segment.

let stopAt = (91 + Math.floor((Math.random() * 43)))
     ||
let stopAt = (181 + Math.floor((Math.random() * 43)))
     ||
let stopAt = (271 + Math.floor((Math.random() * 43)))

// Important thing is to set the stopAngle of the animation before stating the spin.
theWheel.animation.stopAngle = stopAt;
// May as well start the spin from here.
theWheel.startAnimation();
}

Thanks
Eddy

[Lbdevaa]

Did you decided?

[zarocknz]

The code in the example is not valid JavaScript which is why it does not work.

I would simply add the possible options to an array and then use the Math.random() in JavaScript to choose one of the options, at random.

There is a also a getRandomForSegment(int segmentNumber) function in winWheel.js which can be used to pick a random angle inside a segment. I will use this in the example....

let winningSegments = [
    theWheel.getRandomForSegment(4),
    theWheel.getRandomForSegment(7),
    theWheel.getRandomForSegment(9),
    theWheel.getRandomForSegment(10)
];

let stopAt = winningSegments[Math.floor(Math.random() * Math.floor(winningSegments.length));