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gaufung opened this issue · 3 comments
gaufung commented
-
chapter 08
The prof. takes $b_1=1,b_2=5,b_3=6 $ for an example, so
$
\begin{eqnarray*}
x_1 & + & 2x_3 & = & 1 \
& & 2x_3 & = & 3 \
\end{eqnarray*}
$
$
\begin{eqnarray*}
x_1 & = & -2 \
x_3 & = & \frac{3}{2} \
\end{eqnarray*}
$ -
chapter 16
$Pb$ 将会把向量投影在$A$的行空间中
Should be
zlotus commented
Thanks, I've the error in chapter 16.
But I don't get the equations mentioned in chapter 08, could you make a more specific description?
Thank you~
gaufung commented
解法:另所有自由变量取0,则有
X1+2X3 = 0
2X3 = 0
解得X1 = -2 X3=3/2
The Prof. took b1=1,b2=5,b3=6 for example which subjects to b3-b2-b1 =0 condition. So if we set free varibales =0 , we should get X1+2X3 = 1;2X3=3,and solve this equations.
zlotus commented
Sorry, my mistake.
Thanks a lot~