django-ajax

Fast and easy AJAX libraries for django applications.

Requirements

3.x

python >=3.5
django >=2.0

2.x

python >=2.7
django >=1.7,<2.0

Installation

Install django-ajax in your python environment

1- Download and install package:

$ pip install djangoajax

Through Github:

pip install -e git://github.com/yceruto/django-ajax#egg=djangoajax

or simply with:

$ python setup.py install

2- Add 'django_ajax' into the INSTALLED_APPS list.

3- Read usage section and enjoy this feature!

Usage

@ajax Decorator

from django_ajax.decorators import ajax

@ajax
def my_view(request):
    do_something()

When the view does not return anything, you will receive this response (JSON format):

{"status": 200, "statusText": "OK", "content ": null}

Sending content

@ajax
def my_view(request):
    c = 2 + 3
    return {'result': c}

The whole result is converted into a JSON format as part of the content element:

{"status": 200, "statusText": "OK", "content": {"result": 5}}

Combining with others decorators

from django.contrib.auth.decorators import login_required
from django_ajax.decorators import ajax

@ajax
@login_required
def my_view(request):
    # if the request.user is anonymous then this view not proceed
    return {'user_id': request.user.id}

The location or path of the redirection response will be given in the content item, also the status and statusText will reflect what is going on:

{"status": 302, "statusText": "FOUND", "content": "/login"}

Template response

from django.shortcuts import render
from django_ajax.decorators import ajax

@ajax
def my_view(request):
    return render(request, 'home.html')

The JSON response:

{"status": 200, "statusText": "OK", "content": "<html>...</html>"}

Catch exceptions

@ajax
def my_view(request):
    a = 23 / 0  # this line throws an exception
    return a

The JSON response:

{"status": 500, "statusText": "INTERNAL SERVER ERROR", "content": "integer division or modulo by zero"}

AJAXMiddleware

If you are using AJAX at all times in your project, we suggest you activate the AJAXMiddleware described below.

Add django_ajax.middleware.AJAXMiddleware to the MIDDLEWARE_CLASSES list in settings.py and all your responses will be converted to JSON whereas the request was made via AJAX, otherwise it will return a normal HttpResponse.

Caution!

If this middleware is activated you cannot use the @ajax decorator. That will cause double JSON conversion.

AJAXMixin for class-based views

AJAXMixin is an object that call to AJAX decorator.

from django.views.generic import TemplateView
from django_ajax.mixin import AJAXMixin

class SimpleView(AJAXMixin, TemplateView):
    template_name = 'home.html'

The JSON response:

{"status": 200, "statusText": "OK", "content": "<html>...</html>"}

Enjoy And Share!

AlexanderDefuria/django-ajax

django-ajax

Requirements

Installation

Usage

@ajax Decorator

AJAXMiddleware

AJAXMixin for class-based views