chispa provides fast PySpark test helper methods that output descriptive error messages.
This library makes it easy to write high quality PySpark code.
Fun fact: "chispa" means Spark in Spanish ;)
Install the latest version with pip install chispa
.
If you use Poetry, add this library as a development dependency with poetry add chispa --dev
.
Suppose you have a function that removes the non-word characters in a string.
def remove_non_word_characters(col):
return F.regexp_replace(col, "[^\\w\\s]+", "")
Create a SparkSession
so you can create DataFrames.
from pyspark.sql import SparkSession
spark = (SparkSession.builder
.master("local")
.appName("chispa")
.getOrCreate())
Create a DataFrame with a column that contains strings with non-word characters, run the remove_non_word_characters
function, and check that all these characters are removed with the chispa assert_column_equality
method.
import pytest
from chispa.column_comparer import assert_column_equality
import pyspark.sql.functions as F
def test_remove_non_word_characters_short():
data = [
("jo&&se", "jose"),
("**li**", "li"),
("#::luisa", "luisa"),
(None, None)
]
df = (spark.createDataFrame(data, ["name", "expected_name"])
.withColumn("clean_name", remove_non_word_characters(F.col("name"))))
assert_column_equality(df, "clean_name", "expected_name")
Let's write another test that'll fail to see how the descriptive error message lets you easily debug the underlying issue.
Here's the failing test:
def test_remove_non_word_characters_nice_error():
data = [
("matt7", "matt"),
("bill&", "bill"),
("isabela*", "isabela"),
(None, None)
]
df = (spark.createDataFrame(data, ["name", "expected_name"])
.withColumn("clean_name", remove_non_word_characters(F.col("name"))))
assert_column_equality(df, "clean_name", "expected_name")
Here's the nicely formatted error message:
You can see the matt7
/ matt
row of data is what's causing the error (note it's highlighted in red). The other rows are colored blue because they're equal.
We can also test the remove_non_word_characters
method by creating two DataFrames and verifying that they're equal.
Creating two DataFrames is slower and requires more code, but comparing entire DataFrames is necessary for some tests.
from chispa.dataframe_comparer import *
def test_remove_non_word_characters_long():
source_data = [
("jo&&se",),
("**li**",),
("#::luisa",),
(None,)
]
source_df = spark.createDataFrame(source_data, ["name"])
actual_df = source_df.withColumn(
"clean_name",
remove_non_word_characters(F.col("name"))
)
expected_data = [
("jo&&se", "jose"),
("**li**", "li"),
("#::luisa", "luisa"),
(None, None)
]
expected_df = spark.createDataFrame(expected_data, ["name", "clean_name"])
assert_df_equality(actual_df, expected_df)
Let's write another test that'll return an error, so you can see the descriptive error message.
def test_remove_non_word_characters_long_error():
source_data = [
("matt7",),
("bill&",),
("isabela*",),
(None,)
]
source_df = spark.createDataFrame(source_data, ["name"])
actual_df = source_df.withColumn(
"clean_name",
remove_non_word_characters(F.col("name"))
)
expected_data = [
("matt7", "matt"),
("bill&", "bill"),
("isabela*", "isabela"),
(None, None)
]
expected_df = spark.createDataFrame(expected_data, ["name", "clean_name"])
assert_df_equality(actual_df, expected_df)
Here's the nicely formatted error message:
You can easily compare DataFrames, ignoring the order of the rows. The content of the DataFrames is usually what matters, not the order of the rows.
Here are the contents of df1
:
+--------+
|some_num|
+--------+
| 1|
| 2|
| 3|
+--------+
Here are the contents of df2
:
+--------+
|some_num|
+--------+
| 2|
| 1|
| 3|
+--------+
Here's how to confirm df1
and df2
are equal when the row order is ignored.
assert_df_equality(df1, df2, ignore_row_order=True)
If you don't specify to ignore_row_order
then the test will error out with this message:
The rows aren't ordered by default because sorting slows down the function.
This section explains how to compare DataFrames, ignoring the order of the columns.
Suppose you have the following df1
:
+----+----+
|num1|num2|
+----+----+
| 1| 7|
| 2| 8|
| 3| 9|
+----+----+
Here are the contents of df2
:
+----+----+
|num2|num1|
+----+----+
| 7| 1|
| 8| 2|
| 9| 3|
+----+----+
Here's how to compare the equality of df1
and df2
, ignoring the column order:
assert_df_equality(df1, df2, ignore_column_order=True)
Here's the error message you'll see if you run assert_df_equality(df1, df2)
, without ignoring the column order.
Each column in a schema has three properties: a name, data type, and nullable property. The column can accept null values if nullable
is set to true.
You'll sometimes want to ignore the nullable property when making DataFrame comparisons.
Suppose you have the following df1
:
+-----+---+
| name|age|
+-----+---+
| juan| 7|
|bruna| 8|
+-----+---+
And this df2
:
+-----+---+
| name|age|
+-----+---+
| juan| 7|
|bruna| 8|
+-----+---+
You might be surprised to find that in this example, df1
and df2
are not equal and will error out with this message:
Examine the code in this contrived example to better understand the error:
def ignore_nullable_property():
s1 = StructType([
StructField("name", StringType(), True),
StructField("age", IntegerType(), True)])
df1 = spark.createDataFrame([("juan", 7), ("bruna", 8)], s1)
s2 = StructType([
StructField("name", StringType(), True),
StructField("age", IntegerType(), False)])
df2 = spark.createDataFrame([("juan", 7), ("bruna", 8)], s2)
assert_df_equality(df1, df2)
You can ignore the nullable property when assessing equality by adding a flag:
assert_df_equality(df1, df2, ignore_nullable=True)
Python has NaN (not a number) values and two NaN values are not considered equal by default. Create two NaN values, compare them, and confirm they're not considered equal by default.
nan1 = float('nan')
nan2 = float('nan')
nan1 == nan2 # False
Pandas, a popular DataFrame library, does consider NaN values to be equal by default.
This library requires you to set a flag to consider two NaN values to be equal.
assert_df_equality(df1, df2, allow_nan_equality=True)
We can check if columns are approximately equal, which is especially useful for floating number comparisons.
Here's a test that creates a DataFrame with two floating point columns and verifies that the columns are approximately equal. In this example, values are considered approximately equal if the difference is less than 0.1.
def test_approx_col_equality_same():
data = [
(1.1, 1.1),
(2.2, 2.15),
(3.3, 3.37),
(None, None)
]
df = spark.createDataFrame(data, ["num1", "num2"])
assert_approx_column_equality(df, "num1", "num2", 0.1)
Here's an example of a test with columns that are not approximately equal.
def test_approx_col_equality_different():
data = [
(1.1, 1.1),
(2.2, 2.15),
(3.3, 5.0),
(None, None)
]
df = spark.createDataFrame(data, ["num1", "num2"])
assert_approx_column_equality(df, "num1", "num2", 0.1)
This failing test will output a readable error message so the issue is easy to debug.
Let's create two DataFrames and confirm they're approximately equal.
def test_approx_df_equality_same():
data1 = [
(1.1, "a"),
(2.2, "b"),
(3.3, "c"),
(None, None)
]
df1 = spark.createDataFrame(data1, ["num", "letter"])
data2 = [
(1.05, "a"),
(2.13, "b"),
(3.3, "c"),
(None, None)
]
df2 = spark.createDataFrame(data2, ["num", "letter"])
assert_approx_df_equality(df1, df2, 0.1)
The assert_approx_df_equality
method is smart and will only perform approximate equality operations for floating point numbers in DataFrames. It'll perform regular equality for strings and other types.
Let's perform an approximate equality comparison for two DataFrames that are not equal.
def test_approx_df_equality_different():
data1 = [
(1.1, "a"),
(2.2, "b"),
(3.3, "c"),
(None, None)
]
df1 = spark.createDataFrame(data1, ["num", "letter"])
data2 = [
(1.1, "a"),
(5.0, "b"),
(3.3, "z"),
(None, None)
]
df2 = spark.createDataFrame(data2, ["num", "letter"])
assert_approx_df_equality(df1, df2, 0.1)
Here's the pretty error message that's outputted:
DataFrame equality messages peform schema comparisons before analyzing the actual content of the DataFrames. DataFrames that don't have the same schemas should error out as fast as possible.
Let's compare a DataFrame that has a string column an integer column with a DataFrame that has two integer columns to observe the schema mismatch message.
def test_schema_mismatch_message():
data1 = [
(1, "a"),
(2, "b"),
(3, "c"),
(None, None)
]
df1 = spark.createDataFrame(data1, ["num", "letter"])
data2 = [
(1, 6),
(2, 7),
(3, 8),
(None, None)
]
df2 = spark.createDataFrame(data2, ["num", "num2"])
assert_df_equality(df1, df2)
Here's the error message:
TODO: Need to benchmark these methods vs. the spark-testing-base ones
These dependencies are vendored:
The dependencies are vendored to save you from dependency hell.
You are encouraged to clone and/or fork this repo.
This project uses Poetry for packaging and dependency management.
- Setup the virtual environment with
poetry install
- Run the tests with
poetry run pytest tests
Studying the codebase is a great way to learn about PySpark!
Anyone is encouraged to submit a pull request, open an issue, or submit a bug report.
We're happy to promote folks to be library maintainers if they make good contributions.