Binary Lamp Switch Game - Crewate Binary Numbers (from 0 to 127) using Lamps :3 With each Iteration your time becomes less :3 Every 10 seconds the time gets less unless you just have 10s uwu
NOTE: The options Menu content Box is kinda weird, so just try clicking on differnet places a few times uwu
NOTE: Tutorial is currently for the old UI, Textfields have been moved etc
ESC - naviagte Back to menu
Arrow Keys Up/Down: Navigate Main Menu
Enter/Sapcebar: Confirm selection in main menu
ArrowK Keys Left/Right & Sapcebar/Enter: navigate in Tutorial
- The game generates a random decimal number like 42
- You have to translate this number into binary using the lamps
- lamp on = 1 * 2^x, lamp of = 0 * 2^x (x beeing the exponent beeing equal to the lamps number) * Note: the lamp counts from the side where the arrow is pointing to the lamp row, the arrow defines the endianess of the lamp row
- when you have corectly replicated the number the remaining time will be added to your score
- on every 10 iterations your time will get less, but you will always have atleast 10 seconds for a number
- there is a actually a point where the game will end ;3
Plattform | Status | Supported | Tested |
---|---|---|---|
iOS | Testflight | ✔️ | ✔️ |
MacOS | Testflight | ✔️ | ❌ |
Android | WIP | ✔️ | ❌ |
Windows | WIP | ✔️ | ✔️ |
NOTE: Pls edit the build version in the project file to not be the same as the version number
Each lamp becomes a random switch assigned, one random lamps becomes a second random switch
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p0': Position of the lamp lx
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p0: Position of the lamp + padding pad1 (since we dont want the line to start in the middle of the lamp but rather bvelow the lamp)
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p1: p0 extended on the y-axis to the assigned level fx
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p3': Center Position of the Switch sx
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p3: Postion of sx with padding pad2
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p2: p3 extended on the y-axis to the assigned level fx
- Endian Switching (Changes the direction form where you have to read the number in binary)
- Gdoot 4.2.2