seedpart will take a 12 or 24 word seed and generate three different seeds of the same length.
Two of the three generated seeds can be used to recover the original seed phrase.
The process uses a series of XOR operations along with some entropy data to generate shards which do not expose any part of the original seed phrase.
The plaintext module may be useful for securely storing administrative system passwords among three trusted parties. Two parties would need to cooperate in order to recover the administrative password they are holding.
# python
>>> import seedpart
>>> key = 'thank equip quality viable merit garden phone jeans mansion pilot grant toddler crisp velvet ability aim dutch camp actor coconut negative thought color involve'
>>> sp = seedpart.BIP39xor()
>>> sp.split(key)
>>> print(sp)/-------------------------------------------------------------------------------------\
| seedpart SEED SHARDS |
| |
| SHARD 1 + SHARD 2 + SHARD 3 |
--------------------------- | --------------------------- | ---------------------------
Number Word Index | Number Word Index | Number Word Index
--------------------------- | --------------------------- | ---------------------------
1 noble 1197 | 1 engine 595 | 1 ensure 602
2 outer 1258 | 2 sphere 1675 | 2 require 1464
3 repair 1460 | 3 boost 205 | 3 lazy 1011
4 slow 1633 | 4 disorder 507 | 4 apart 82
5 health 849 | 5 ticket 1805 | 5 beef 160
6 guard 826 | 6 decline 455 | 6 elite 576
7 tag 1769 | 7 leaf 1013 | 7 swear 1756
8 witness 2021 | 8 mention 1112 | 8 knock 990
9 gas 768 | 9 trap 1850 | 9 retire 1471
10 awful 133 | 10 reform 1442 | 10 pill 1318
11 chapter 307 | 11 duck 542 | 11 road 1495
12 glory 796 | 12 liberty 1031 | 12 tenant 1784
13 monkey 1145 | 13 route 1508 | 13 average 126
14 hub 884 | 14 orient 1252 | 14 coil 362
15 reform 1442 | 15 refuse 1443 | 15 abandon 0
16 sport 1685 | 16 subject 1727 | 16 curious 431
17 seek 1560 | 17 manual 1083 | 17 elite 576
18 chapter 307 | 18 allow 53 | 18 flee 710
19 combine 367 | 19 consider 378 | 19 bench 168
20 fan 662 | 20 lawsuit 1009 | 20 recall 1435
21 few 684 | 21 shoe 1587 | 21 helmet 855
22 chimney 320 | 22 similar 1607 | 22 coyote 397
23 among 63 | 23 clean 338 | 23 story 1716
24 potato 1350 | 24 ten 1783 | 24 tired 1813
--------------------------- | --------------------------- | ---------------------------
# python
>>> import seedpart
>>> sp = seedpart.BIP39xor()
>>> shard1 = 'noble outer repair slow health guard tag witness gas awful chapter glory monkey hub reform sport seek chapter combine fan few chimney among potato'
>>> shard3 = 'ensure require lazy apart beef elite swear knock retire pill road tenant average coil abandon curious elite flee bench recall helmet coyote story tired'
>>> sp.join([shard1, None, shard3])
>>> print(sp)/-----------------------------------------------------------\
| seedpart SEED |
| |
-------------------------------------------------------------
Number Word Index Number Word Index
--------------------------- ---------------------------
1 thank 1790 13 crisp 413
2 equip 609 14 velvet 1936
3 quality 1401 15 ability 1
4 viable 1946 16 aim 42
5 merit 1116 17 dutch 547
6 garden 765 18 camp 262
7 phone 1308 19 actor 21
8 jeans 957 20 coconut 359
9 mansion 1082 21 negative 1183
10 pilot 1319 22 thought 1799
11 grant 813 23 color 365
12 toddler 1819 24 involve 945
--------------------------- ---------------------------
Key shards may include abbreviated words as long they are not ambiguous. For example, you can use cata in place of catalog.
You can reconstruct the seed by hand with the following procedure:
- Convert each shard into a list of numbers, where each number is the line the word appears in the BIP39 list minus 1 (e.g. "abondon" = 0, "monkey" = 1145).
- If you are missing shard 0:
- XOR each number from both shards to generate a third shard. For shard 1, start with the last word and work up. For shard 2, start with the first word and work down.
- If you are missing shard 1:
- XOR each number from both shards to generate a third shard. For both shards start with the first word.
- Reverse the list generated from the previous step.
- If you are missing shard 2:
- Skip to next step.
- XOR shard 0 and shard 1 to recover the original seed phrase.
>>> import seedpart
>>> sobj = seedpart.plaintextxor()
>>> sobj.split('horse battery')
>>> print(sobj)Shard 1: 523d79712f41276a66556e765c
Shard 2: 3a520b024a61450b12210b0425
Shard 3: 773972503d4a620b2c57652466
>>> sobj2 = seedpart.plaintextxor()
>>> sobj2.join(['523d79712f41276a66556e765c', None, '773972503d4a620b2c57652466'])
>>> print(sobj2)Plaintext key: horse battery
>>> sobj3 = seedpart.plaintextxor()
>>> sobj3.join(['523d79712f41276a66556e765c', None, '3a3427596833665d3e4e4c232e'])
>>> print(sobj3)Plaintext key: h[jwvf�!}0�4
| Donation Method | Address | QR Code |
|---|---|---|
| Bitcoin Cash (BCH) | 1HSycjR3LAZxuLG34aEBbQdUSayPkh8XsH |  |
| Bitcoin (BTC) | 1HY3jPYVfE6YZbuYTYfMpazvSKRXjZDMbS |  |