Argv

Easy command line parsing in C++

The goal is to allow easy parsing of command-line options with minimal boilerplate and low runtime overhead (in time & space). Easy things should be easy, and harder things should be possible.

Example:

#include "Argv.hpp"
#include <iostream>
#include <cassert>

int main(int argc, char** argv)
{
    Argv args(argc, argv, R"(
Usage: {name} [options] foo....

Options:

--output (-o) FILE
    Write the results to FILE

--period (-p) SECONDS
    Duration in each period.  Units are floating point seconds

--debug (-d)
    Enable debug logging

--verbose (-v)
    Be verbose.  Multiple occurrences increase verbosity

)");

    char const* output = nullptr;
    double period = 10.0;
    bool debug = false;
    int verbosity = 0;
    while (args) {
        args.option('o', "--output", output);
        args.option('p', "--period", period);
        args.option('d', "--debug", debug);
        args.counter('v', "--verbose", verbosity);
    }

That all that's needed for parsing.

After the while loop, argv contains only the non-option arguments. argv[0] is the program name. argv[i] is the i'th non-option argument.

The help text (the 3rd argument to the Argv constructor) is merely informative. Unlike some other argument parsers, Argv does not try to interpret this text. If Argv finds the --help or -h options, Argv writes this help text to stdout and then invokes exit(0). Argv replaces {name} with the application's name (the basename of argv[0] which is also available as args.name()).

Next we can verify we were passed the right number of non-option arguments:

    if (argc < 2)
        args.try_help("wrong usage");

Then proceed with whatever the application would do. For example:

    if (output)
        std::cout << "Output: " << output << '\n';
    else
        std::cout << "No output specified\n";

    std::cout << "Period: " << period << '\n';
    if (debug)
        std::cout << "Debug logging enabled\n";
    std::cout << "Verbosity: " << verbosity << '\n';

    for (int i = 0; i < argc; ++i)
        std::cout << "argv[" << i << "]=" << argv[i] << '\n';
    assert(argv[argc] == nullptr);
}

Running this example:

$ g++ -Wall -Werror -std=c++17 ex1.cpp Argv.cpp
$ ./a.out -vvv -o hello world
Output: hello
Period: 10
Verbosity: 3
argv[0]=./a.out
argv[1]=world
$
$
$ ./a.out --help

Usage: a.out [options] foo....

Options:

--output (-o) FILE
    Write the results to FILE

--period (-p) SECONDS
    Duration in each period.  Units are floating point seconds

--debug (-d)
    Enable debug logging

--verbose (-v)
    Be verbose.  Multiple occurrences increase verbosity

$

Short options can be bundled: -dvvv is the same -d -v -v -v.

For options that require an additional argument, the argument can be separated or not. -ofoo versus -o foo. Or --output=foo versus --output foo.

For arithmetic options (integer or floating point), you may specify lower and upper bounds:

    int count = 1;
...
    args.option('n', "--count", count, 1, 10);

With --count=42, for example, the program would throw std::runtime_error.

For more complex validation, the option functions return true to indicate when an option was matched:

    if (args.option('x', "--extra", extra)) {
        do_more_validation(extra);
    }

Options may appear in any order, before or after non-option arguments.

A double-hyphen -- ends argument processing. Any arguments after the -- are not considered options even if they begin with a hyphen.

A single hyphen - is always considered to be a non-option argument.

Memory Considerations

The Argv class assumes the argv argument is the traditional array of pointers to legacy C strings. Argv will modify the argv array to remove option arguments (and update argc accordingly). Argv always maintains the condition that argv[argc]==nullptr. Argv never modifies the pointed-to strings of argv[].

You may safely destroy the Argv object after parsing is complete. The results of the parsing remain valid. In particular:

the argv array remains valid
all of the argv[] pointers remain valid
the value returned from Argv::name remains valid -- it points at or into the argv[0] string
a char* gotten from option remains valid -- it points at or into one of the original argv[] strings

The help_text argument to the Argv constructor must remain valid at least until the Argv object is destroyed. For example, don't do this:

    Argv args(argc, argv, std::string{...}.c_str()); // don't do this

If you must construct the help text at runtime, use a std::string object whose lifetime is greater than the Argv object's.

    std::string help_text{ ... };
    Argv args(argc, argc, help_text.c_str());

MichaelCook/Argv

Argv

Memory Considerations